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Nadya [2.5K]
3 years ago
11

HELP DUE 3 MINUTESSSSD

Physics
1 answer:
Delvig [45]3 years ago
6 0

Answer:

Break down small pebbles and sediments, like sand

Break down large rocks like mountains

Explanation:

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The distance versus this plot for a particular object shows a quadratic relationship. Which column of distance data is possible
SOVA2 [1]

Answer:

A

Explanation:

In Column A, the pattern is 1², 2², 3², etc.  So x(t) = t², which is quadratic.

In Column B, the pattern is 2*1, 2*2, 2*3, etc.  So x(t) = 2t, which is linear.

In Column C, the pattern is 9*1, 9*2, 9*3, etc.  So x(t) = 9t, which is linear.

In Column D, the pattern is 1/1, 1/2, 1/3, etc.  So x(t) = 1/t, which is reciprocal.

In Column E, the pattern is 1/1², 1/2², 1/3², etc.  So x(t) = 1/t², which is reciprocal.

5 0
3 years ago
A thin plastic rod of length 2.5 m is rubbed all over with wool, and acquires a charge of 75 nC, distributed uniformly over its
Colt1911 [192]

Answer:

find out the le

Explanation:

3 0
2 years ago
What is the density of 15 cm3 and 3 g?
lilavasa [31]

Answer:

0.2

Explanation:

3/15

6 0
2 years ago
Some superconductors are capable of carrying a very large quantity of current. If the measured current is 1.00 ´ 105 A, how many
Zielflug [23.3K]

Answer:

The 6.25 \times 10^{23} electrons are moving through the superconductor per second.

Explanation:

Given :

Current I = 1 \times 10^{5} A

Charge of electron e = 1.6 \times 10^{-19} C

Time t = 1 sec

From the formula of current,

Current is the number of charges flowing per unit time.

   I = \frac{ne}{t}

Where n = number of charges means in our case number of electrons

   n = \frac{It}{e}

   n = \frac{1 \times 10^{5} }{1.6 \times 10^{-19} }

   n = 6.25 \times 10^{23}

Therefore, 6.25 \times 10^{23} electrons are moving through the superconductor per second.

5 0
3 years ago
If the angle of refraction is 20 degrees what is the angle of incidence​
Romashka-Z-Leto [24]

Answer:

13.1

Explanation:

that's what I'm gonna go with, but u can research more

5 0
2 years ago
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