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BaLLatris [955]
3 years ago
15

A layer of oil (n = 1.38) floats on an unknown liquid. A ray of light originates in the oil and passes into the unknown liquid.

The angle of incidence is 65.0°, and the angle of refraction is 53.0°. What is the index of refraction of the unknown liquid?
Physics
1 answer:
Vinil7 [7]3 years ago
4 0

Answer:

Refractive index of unknown liquid = 1.56

Explanation:

Using Snell's law as:

n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}

Where,  

{\theta_i}  is the angle of incidence  ( 65.0° )

{\theta_r} is the angle of refraction  ( 53.0° )

{n_r} is the refractive index of the refraction medium  (unknown liquid, n=?)

{n_i} is the refractive index of the incidence medium (oil, n=1.38)

Hence,  

1.38\times {sin65.0^0}={n_r}\times{sin53.0^0}

Solving for {n_r},

Refractive index of unknown liquid = 1.56

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Murljashka [212]

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Explanation:

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8 0
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How are the planets sizes related to their surface gravity
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What average force is required to stop a 980 kg car in 9.0 s if the car is traveling at 91 km/h ?
kozerog [31]
Newton's second law of motion:
F=ma
a =  \frac{v}{t}
You convert from km/h to m/s by dividing by 3.6:
v = 91 \div 3.6
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