Answer:
6.05 cm
Explanation:
The given equation is
2 aₓ(x-x₀)=( Vₓ²-V₀ₓ²)
The initial head velocity V₀ₓ =11 m/s
The final head velocity Vₓ is 0
The accelerationis given by =1000 m/s²
the stopping distance = x-x₀=?
So we can wind the stopping distance by following formula
2 (-1000)(x-x₀)=[]
x-x₀=6.05* m
=6.05 cm
Answer:
W= 565.42 J
Explanation:
Given that
mass , m =20.5 kg
displacement = 5.93 m
Applied force ,F= 95.3501 N
Coefficient of friction ,μ = 0.389
We know that work done by force F is given as
W= F .d
d=Displacement
F=Force
W=Work
W= 95.3501 x 5.93 J
W= 565.42 J
Therefore the work done by applied force will be 565.42 J.
175km per hour
That’s the speed it was going.
See attached photos for the solution:
k is the rate constant
T is the absolute temperature (in kelvins)
A is the pre-exponential factor, a constant for each chemical reaction. According to collision theory, A is the frequency of collisions in the correct orientation
Ea is the activation energy for the reaction (in the same units as R*T)
R is the universal gas constant.
Answer:
The speed of the particle is 2.86 m/s
Explanation:
Given;
radius of the circular path, r = 2.0 m
tangential acceleration, = 4.4 m/s²
total magnitude of the acceleration, a = 6.0 m/s²
Total acceleration is the vector sum of tangential acceleration and radial acceleration
where;
is the radial acceleration
The radial acceleration relates to speed of particle in the following equations;
where;
v is the speed of the particle
Therefore, the speed of the particle is 2.86 m/s