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castortr0y [4]
2 years ago
12

Find the area of the triangle. Single choice.

Mathematics
2 answers:
Fittoniya [83]2 years ago
8 0

Answer:

48 square units

Step-by-step explanation:

The area of a triangle is calculated by multiplying height to the base and that divided by two

The height of the given triangle is 8 units and the base is 12 units

8×12÷2 = 48

Alexxx [7]2 years ago
6 0
<h2><em><u>Answ</u></em><em><u>er</u></em><em><u>:</u></em><em><u>-</u></em></h2>

\pink{\bigstar} Area of the triangle is \large\leadsto\boxed{\tt\purple{48 \: square \: units}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>• <u>Knowledge Required:-</u></h3>

✯ In order to find the area of a triangle we must know about 2 parameters i.e, height and base of the traingle.

✯ We need to count the number of grids present inside the triangle or forming the triangle vertically to know about the height of the triangle. Similarly, counting the grids horizontally will give us the base of the triangle.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

<h3>• <u>Solution</u><u>:</u><u>-</u></h3>

Following the above steps we get to know the required parameters.

  • Height = 8 units

  • Base = 12 units

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Now moving on, there is a formula to find out the area of a triangle.

\pink{\bigstar} \large\underline{\boxed{\bf\green{Area_{(triangle)} = \dfrac{1}{2} \times b \times h}}}

where,

  • b = base of the triangle

  • h = height of the triangle

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• <u>Substitut</u><u>ing</u><u> in</u><u> the</u><u> Formula</u><u>:</u><u>-</u>

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf Area_{(triangle)} = \dfrac{1}{2} \times 12 \times 8

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

➪ \sf Area_{(triangle)} = \dfrac{1}{2} \times 96

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

★ \bold\red{Area_{(triangle)} = 48 \: square \: units}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Therefore, the Area of the given triangle is 48 square units.

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Given:

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You have to make a cos graph that starts its minimum and of -2, has an amplitude of 10, a period of 10 and  a maximum of 18.
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-10cos((π/5)x) has a minimum of -10 and maximum of 10 instead of a minimum of -2 and maximum of 18, to fix this we add 8 to -10cos((π/5)x) to get -10cos((π/5)x)+8 which does have a minimum of -2 and maximum of 18.

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8 0
3 years ago
3. (05.06 MC)
AveGali [126]

Answer:

Step-by-step explanation:

y > 3x + 10

y < -3x - 1

<h3> Part A:</h3>

You'd graph the given systems of linear inequalities the same way as you graph the linear equations.  

To graph y > 3x + 10, plot the y-intercept, (0, 10), then use the slope, m = 3 (rise 3, run 1), to plot other points on the graph.  Use a dashed line (because of the ">" symbol).  

Follow the same steps for the other linear inequality. Plot the y-intercept, (0, -1), then use the slope, m = -3 (down 3, run 1) to plot other points. Use a dashed line (because of the "<" symbol).  

Pick a test point on either side of the boundary line and plug it into the original problem.  This will help determine which side of the boundary line is the solution.  Plug in a test point that is not on the boundary line.

Use the point of origin, (0, 0) as the test point. Plug in these values into the given systems of linear inequalities to see whether it will provide a true statement.  

y > 3x + 10

0 > 3(0) + 10

0 > 0 + 10

0 > 10 (False statement).  

y < -3x - 1

0 < -3(0) - 1

0 < 0 - 1

0 < -1 (false statement).  

Since the point of origin provided a false statement to the given systems of linear inequalities, you must shade the half-plane region where it doesn't contain the test point.  

<h3>Part B: </h3>

You'll do the same process as what I've done for the test point. Plug in the values of (8, 10) into the given systems of linear inequalities. If it provides a false statement, then it means that it is not a solution to the system.  

y > 3x + 10

10 > 3(8) + 10

10 > 24 + 10

10 > 34 (False statement).  

y < -3x - 1  

10 < -3(8) - 1

10 < -24 - 1

10 < -25 (false statement).  

Therefore, (8, 10) is not a solution to the system.    

8 0
3 years ago
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