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12345 [234]
3 years ago
13

Does anyone know how to solve this problem?

Mathematics
1 answer:
marissa [1.9K]3 years ago
8 0
7? Is seems that the 4 is being added with +2 when it got bigger so I’m thinking the 5 would be the same thing +2 equals 7..that’s what I’m thinking
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If a= 4.2 to (1dp) and b = 18 (to the nearest whole number), Find the lower and upper bound of the following: ((a+b)/a)
Rainbow [258]

Answer:

Lower bound = 5.2

Upper bound = 5.4

Step-by-step explanation:

If a= 4.2 to (1dp):

Upper bound = 4.2 + 0.05 = 4.25

Lower bound = 4.2 - 0.05 = 4.15

If b = 18 (to the nearest whole number)

Upper bound = 18 + 0.5 = 18.5

Lower bound = 18 - 0.5 = 17.5

Therefore:

Lower bound of ((a+b)/a) = ((4.15 + 17.5) / 4.15) = 5.2 to 1 decimal place

Upper bound of ((a+b)/a) = ((4.25 + 18.5) / 4.25) = 5.4 to 1 decimal place

The upper and lower bound are calculated to one decimal place.

7 0
3 years ago
What is the slope of the line perpendicular to the graph of 3x + 4y = 12?
WINSTONCH [101]

Answer:

{ \tt{slope =    \frac{1}{3} }}

Step-by-step explanation:

{ \tt{m _{1} \times m _{2}  =  - 1}} \\ { \tt{ - 3 \times m _{2}  =  - 1}} \\ { \tt{m _{2} =  \frac{1}{3}  }}

7 0
3 years ago
Given: △ABC, D∈ AC m∠ABC=m∠BDA AB=2, AC=4 Find: AD and DC
sveta [45]

Answer:

The value of AD=1 and DC=3

Step-by-step explanation:

Given: ΔABC, D∈ AC m∠ABC=m∠BDA,  AB=2, AC=4

Diagram: Please find attachment.

To find: AD=? and DC=?

Calculation:

In ΔABC and ΔADB

   ∠ABC=∠ADB          (Given)

        ∠A=∠A               (Common)

Therefore,  ΔABC ≈ ΔADB  by AA similarity

If two triangles are similar then ratio their corresponding sides are equal

Therefore,

\dfrac{AD}{AB}=\dfrac{AB}{AC}

where, AD=?, AB=2, AC=4

\dfrac{AD}{2}=\dfrac{2}{4}

AD=\dfrac{2\times 2}{4}=1

AD=1

AD+DC=AC

1+DC=4

DC=4-1

DC=3

Hence, The value of AD=1 and DC=3

7 0
3 years ago
Read 2 more answers
What is 1/8 times 20?
strojnjashka [21]
The answer is 2.5, your welcome ;)
7 0
3 years ago
If I had a 2% solution, added 2 ounces to a gallon (128 ounces) What is the final concentration of the solution.
Ne4ueva [31]
<span>A 2% solution of chlorohexidine added to 126 oz of water. The total oz 128.

Solute: chlorohexidine, 2%=0.02
solvent: water (0%)

Concentration, C, volume V
CV=c1v1+c2v1
128C=0.02*2 + 0.00*126 = 0.04

Concentration
C=0.04/128 = 0.0003125 = 0.03125%</span>
6 0
4 years ago
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