Answer:
Question 9: Variables: (smallest) s, q, r (largest)
Question 10: 5 whole numbers (7, 8, 9, 10, and 11)
Step-by-step explanation:
For question nine, there are two given statements... s=q-2 and q<r. Say we plug in 10000 (a really big #) in for q, then we would get s=9998 and r>10000. This way, we can see that s would be the smallest, then q, and r is the largest. <em>(q<r can be written as r>q)</em>
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For question 10, it states 
. This can be split into 
and 
. When x is 12 in the first equation then 
and when x is 6 in the second equation 
(0.5 is also 
). Therefore, x must be a whole number less than 12 and greater than 6, and it cannot be either 12 or 6. Whole numbers between 6 and 12 are 7, 8, 9, 10, and 11 or 5 whole numbers.
E would be (-8,4), F would be (16,-8) and G would be (-24,-16). This is the correct answer. I hope this helps.
90 would be the largest then 59,48, -56, -80, and leaving -84 to be the smallest
Answer:
Whatever is raised to the power of 0 is 1
SO the answer is 1
Answer:
- rational
- irrational
- irrational
- irrational
- √7, it is irrational
Step-by-step explanation:
A <em>rational</em> number is one that can be expressed as the ratio of two integers. All fractions that have integer numerators and (non-zero) denominators are <em>rational</em> numbers. Any finite decimal number, or any repeating decimal number, is a rational number. These can always be expressed as the ratio of two integers. For example, 0.4040... = 40/99, and 0.286 = 286/1000.
To make an irrational sum, at least one of the contributors must be irrational. You want an irrational 2-number sum that has 7/8 as one of the contributors. Since 7/8 is rational, the other contributor must be irrational.
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<u>Step 1</u>. The number 7/8 is <em>rational</em>.
<u>Step 2</u>. The desired sum is <em>irrational</em>.
<u>Step 3</u>. The rule <em>rational + </em><em>irrational</em><em> = irrational</em> applies.
<u>Step 4</u>. An <em>irrational</em> number must be chosen.
Step 5. √7 will produce an irrational sum, because <em>it is irrational</em>.
