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3 years ago

11

Chemistry

1 answer:

Rama09 [41]3 years ago

3 0

Answer: 0.695 mol/L

Explanation:

To find the final concentration of the solution, we must first identify the moles of the solute (NaNO₃):

moles = mass ÷ molar mass

∴ moles of NaNO₃ = 325 g ÷ 84.995 g/mol

= 3.824 mol

Now, since the final volume is 5.5 L and this volume contains the 3.824 moles of NaNO₃,

then the molarity of the solution = 3.824 mol ÷ 5.5 L

= 0.695 mol/L

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Read 2 more answers

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Explanation:

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4 years ago

A chemist prepares a solution of zinc nitrate Zn(NO3)2 by measuring out 78.3g of zinc nitrate into a 350ml volumetric flask and

Anvisha [2.4K]

Answer:

M = 1.18 mol/L

Explanation:

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

$n = \frac{w}{n}$

n = moles ,

w = given mass ,

m = molecular mass .

From the information of the question ,

w = 78.3 g

As we known ,

molecular mass of $Zn(NO_3)_2$ is 189.36 g/mol

m = 189.36 g/mol

moles can be calculated as -

$n = \frac{w}{n}$

$n = \frac{78.3g}{189.36 g/mol}$

n = 0.413 mol

MOLARITY -

Molarity of a substance , is the number of moles present in a liter of solution .

$M=\frac{n}{V}$

M = molarity ( unit = mol / L or M )

V = volume of solution in liter ( unit = L ),

n = moles of solute ( unit = mol ),

From the question ,.

V = 350 mL

Since , 1 mL = 10⁻³ L

V = 0.350 L

n = 0.413 mol

Molarity can be calculated as -

$M=\frac{n}{V}$

$M=\frac{0.413}{0.350}$

M = 1.18 mol/L

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3 years ago