Answer: Zero-emission vehicles have no tailpipe emissions, no emissions from gasoline, and no emission-control systems, which deteriorate over time.
Explanation:
Answer:
The answer to your question is letter E. 288.4 g/mol
Explanation:
Data
Number of carbons = 19
mass percent of carbon = 79.12
molar mass = ?
Process
1.- Calculate the molar mass of 19 atoms of carbon
Atomic mass of carbon = 12 g
Atomic mass of 19 atoms of carbon = 228 g
2.- Use proportions to calculate the mass of testosterone
228 g --------------- 79.12 %
x -------------- 100 %
x = (228 x 100) / 79.12
Simplify
x = 22800 / 79.12
Molar mass of testosterone = 288.2 g
Explanation:
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Answer:
Aluminium (Al): (3*2)+(5*2)=16
Sulphor (S): (3*1)=3
Oxygen (O): (4*3)+(3*1)=15
Answer:
204g of NH3
Explanation:
The balanced equation for the reaction is given below:
N2 + 3H2 —> 2NH3
Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:
From the balanced equation above,
1 mole of N2 reacted to produce 2 moles of NH3.
Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.
Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:
Number of mole of NH3 = 12 moles.
Molar mass of NH3 = 14 + (3x1) = 17g/mol
Mass of NH3 =..?
Mass = mole x molar mass
Mass of NH3 = 12 x 17
Mass of NH3 = 204g.
Therefore, 204g of NH3 will be produced from the reaction.