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3 years ago

Please help with 1 and 3! Please tell me the answer! I'm crying in confusion! :(

Mathematics

1 answer:

Aliun [14]3 years ago

6 0

Don't cry please :(

1:
To find the Average (mean). Add up all the numbers together. Then divide by how many numbers there are.

So use the chart and do what I said :)

2:

To find the mean: Add up all the numbers together. Then divide by how many numbers there are.

To find the median: Put all the numbers in least to greatest. Then if there is a odd amount of numbers. It would be the number in the middle.

To find the mode: The mode is the number that occurs the most.

So use the chart and do what I said :)

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35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

step 1

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

step 2

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

Find the area of the larger circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago

I Need Help Wit My Assignments And I'm A Senior I HAVE TO GRADUATE

NikAS [45]

What is your question ? for help !

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3 years ago

Is the relation in this table a function. Explain Input: 2,4,6,8,10 output: 1,2,3,4,3

ANEK [815]

Answer:

Yes.

Step-by-step explanation:

This relation is a function because each input has one and only one output, i.e. 2 yields 1, 4 yields 2, 6 yields 3, 8 yields 4 and 10 has an output of 3. Therefore, it is a function.

7 0

3 years ago

Find the perimeter of the quadrant. Use 3.143.14 as an approximation for \piπ.

solniwko [45]

Answer: 19.625 cm (Formula is 2πr)

Steps: 1.) 3.14 * 12.5 = 39.25

2.) 39.25 * 2 = 78.5

3.) 78.5 / 4 = 19.625 (using the 4 because the area is a fourth of a whole circle)

6 0

3 years ago

The y-intercept in the linear equation y = -1/10x – 2 is_[blank]

shtirl [24]

The y - intercept is -2

5 0

3 years ago

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