The traveler's total displacement is 53.2 km.
The shortest distance between a particle's starting position and destination is referred to as its displacement vector. Displacement has a distinct physical magnitude than distance. Let's use the motion of a particle making a complete circle as an example. The displacement in this motion is zero, yet the distance traveled is equal to the circle's circumference. The individual displacement vectors are as follows: d1
=22^ikm→d2
= (29.7cos45i29.7sin45) kmd3=104jkm
The traveler's complete disadvantage is,
→d=→d1+→d2+→d3→d
=22^ikM+29.7
cos45^−29.7sin45o) km−10.4^j km→
d=(43^i−31.4^j) km
The magnitude of the total displacement is,
d=√432+31.4/2Km d≈53.2km
The direction is,
θ=tan−1(−31.4/43)
θ=−36.1or 36.1 south of east.
Learn more about displacement here-
brainly.com/question/11934397
#SPJ9
Frame of reference, in simplest terms, describes the state of motion of the observer. The frame of reference may also be described by using a set of coordinates, time and motion. We formulate all our equations and solve them using the frame of reference.
Electrons have a smaller wavelength than visible light, leading to higher resolution.
