Answer:
10 m
Explanation:
Weight = 10 N
mg = 10
m = 10 / 10 = 1 kg
g = 10 m/s^2
Initial mechanical energy = 40 J
Final mechanical energy = 140 J
change in total energy = 140 J – 40 J = 100 J
At the maximum vertical height, the velocity = 0 m/s
So,it has only potential energy at maximum height
P = m x g x h
100 = 1 x 10 x h
h = 10 m
The conductor which has a resistance approximately equals to zero.
Answer:
2.54 μA
Explanation:
The current I in the wire is I = ∫∫J(r)rdrdθ
Since J(r) = Br, in the radial width of 13.1 μm, dr = 13.1 μm. r = 1.50 mm. We have a differential current dI. We remove the first integral by integrating dθ from θ = 0 to θ = 2π.
So, dI = J(r)rdrdθ ⇒ dI/dr = ∫J(r)rdθ = ∫Br²dθ = Br²∫dθ = 2πBr²
Now I = (dI/dr)dr evaluate at r = 1.50 mm = 1.50 × 10⁻³ m and dr = 13.1 μm = 0.013 mm = 0.013 × 10⁻³ m
I = (2πBr²)dr = 2π × 2.34 × 10 A/m³ × (1.50 × 10⁻³ m)² × 0.013 × 10⁻³ m = 2544.69 × 10⁻⁹ A = 2.54 × 10⁻⁶ A = 2.54 μA
Answer:
12294.31 m/s
Explanation:
Momentum = (mass)(velocity)
Momentum before = Momentum after
(momentum of bullet)+(momentum of block)=(momentum of bullet and block)
0.035v+50(0)=(0.035+50)(8.6)
0.035v=430.301
v=12294.3142857m/s
Multiply field strength (N/kg) by mass (kg) to get weight (N)
At the start, the car is carrying
4.7 kg * (9.8 N/kg) = 46.06 N
of fuel.
At the end, it is carrying
3.0 kg * (9.8 N/kg) = 29.4 N.
Assuming the car remains completely intact, its weight was reduced by
46.06 N - 29.4 N = 16.66 N.