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3 years ago

Can someone explain E=mc2 In FULL detail please

1 answer:

8 0

Einstein's Big Idea homepage. E = mc2. It's the world's most famous equation, but what does it really mean? "Energy equals mass times the speed of light squared." On the most basic level, the equation says that energy and mass (matter) are interchangeable; they are different forms of the same thing.

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Place a small object on the number line below at the position marked zero. Draw a circle around the object. Mark the center of t

Murrr4er [49]

Can you post a picture of the whole thing please

6 0

3 years ago

A gymnast does a one-arm handstand. The humerus, which is the upper arm bone between the elbow and the shoulder joint, may be ap

igor_vitrenko [27]

Answer:

$= 5.241 \times 10^{-5} m$

Explanation:

Given:

Length of cylinder is, L = 0.27 m

Outer radius of cylinder is, r_out = 1.12×10^{-2} m

Inner radius of cylinder is, r_in = 3.9×10^{-3} m

Mass of person, m = 60 kg

Young's modulus , Y = 9.4×10^9 N/m2

(a)

Compressional strain of humerous is,

$Strain = \frac{Stress}{Young's\ modulus}$

$\frac{\Delta L}{L_0} = \frac{\frac{F}{A}}{Y}$

$= \frac{(mg)}{\pi(r_out^2 - r_in^2 )Y}$

$= \frac{(60 kg)(9.8 m/s2 )}{(\pi)[( 1.12\times 10^{-2})^2 - (3.9\times 10^{-3} m)^2] (9.4\times 10^9 N/m2 )}[tex] [tex]= 1.80\times 10^{-4} m$

(b) Let assume that humerous is compressed by ΔL

Since, strain = ΔL/L0

$(1.80 \times 10^{-4} m) = ΔL / 0.29 m$

Thus,

$ΔL = (4.56 \times 10^{-4} m)(0.29 m)$

$= 5.241 \times 10^{-5} m$

7 0

3 years ago

How much time is needed for a 15,000 W engine to do 1,800,000 J of work? (Power: P = W/t)

vovikov84 [41]

To solve for this we need to use the formula P = W/T (Power = Work/Time).
Since we do not have time, we shall switch up the formula.
Our new formula is T = W/P (Time = Work/Power).
We have 1,800,000 J of work, and 15,000 W of power.
1,800,000/15,000 = 120.
It will take 120 (insert measure of time here).
I hope this helps!

4 0

3 years ago

Read 2 more answers

An object stays at rest until what happens to it?

bixtya [17]

D. an outside or unbalanced force acts upon the object.

4 0

3 years ago

A block of mass 1.3 kg is resting at the base of a frictionless ramp. A bullet of mass 50 g is traveling parallel to the ramp su

aleksandrvk [35]

Answer:

s = 2.65 m

Explanation:

given,

mass of block,M = 1.3 Kg

mass of bullet,m = 50 g = 0.05 Kg

speed of bullet,u = 250 m/s

speed of bullet after collision,v = 100 m/s

distance traveled by the block = ?

Assuming the angle of inclination of ramp equal to 40°

calculating the speed of the block

using conservation of momentum

M u' + m u = m v + M v'

initial speed of the block is equal to zero

0 + 0.05 Kg x 250 = 0.05 x 100 + 1.3 x v'

1.3 v' = 7.5

v' = 5.77 m/s

now, calculation of acceleration

equation the horizontal component

-mg sin θ = ma

a = - g sin θ

a = - 9.8 x sin 40°

a = -6.29 m/s²

using equation of motion for the calculation of distance moved by the block

v² = u² + 2 a s

0² = 5.77² + 2 x (-6.29) x s

12.58 s = 33.29

s = 2.65 m

hence, the distance moved by the block is equal to 2.65 m

3 0

4 years ago