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3 years ago

Can someone explain E=mc2 In FULL detail please

1 answer:

8 0

Einstein's Big Idea homepage. E = mc2. It's the world's most famous equation, but what does it really mean? "Energy equals mass times the speed of light squared." On the most basic level, the equation says that energy and mass (matter) are interchangeable; they are different forms of the same thing.

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Draw the model of an atom with an atomic number of 7 and a mass number of 15. How many valence electrons are in this atom.

o-na [289]

Answer:

There are 5 valence electrons

Explanation:

Valence electrons are electrons found in the outermost shell of an atom.

7 0

3 years ago

What maximum upward acceleration can it give the elevator without breaking?.

MariettaO [177]

The maximum upward acceleration that the elevator can have without breaking is = 10.36m/s².

<h3>How to calculate maximum upward acceleration?</h3>

To calculate the maximum acceleration of the elevator we must take into account Newton's second law and its formula that takes into account the following aspects:

F = Is the force applied in newtons.
m = Is the mass of the object in kilograms.
a = Is the acceleration of the object in meters per second squeared.

F = m × a

According to the above, we apply the values we have as follows:

a = $\frac{F}{m}$

a = $\frac{21750N}{2100Kg}$

a = 10.36 m/s²

Note: This question is incomplete because some information is missing. Here is the complete information.

Learn more about acceleration in: brainly.com/question/13312735

7 0

3 years ago

In two or more complete sentences, describe the purpose and outcome of the Miller Urey experiment.

Rama09 [41]

Miller Urey experiment's purpose was to test the chemical origin of life under the conditions supposed to be present on the early Earth.
The scientists Miller and Urey heated a mixture of water, ammonia, methane and hydrogen in a sterile flask until it evaporated water to produce water vapour. Electric sparks were passed through the mixture of water vapour and gases, simulating lightning. The experiment was done during one week. After a week, the contents were analysed and Miller and Uray proved that several organic compounds could be formed spontaneously by simulating the conditions of Earth's early atmosphere.

7 0

4 years ago

A stargazer has an astronomical telescope with an objective whose focal length is 195 cm and an eyepiece whose focal length is 1

Colt1911 [192]

Answer:

The best angular magnification is

-375

Explanation:

Fe = Fo - L

From the question, (Fo) = 1.08 cm while (L) = 0.56cm

Thus, Fe = 1.08 - 0.56 = 0.52cm

Now, let's apply the angular magnification equation ;

M = - Di/Do

Where Di is the distance from the lens to the image and Do is the distance of the object to the lens.

In this question, Di is represented by f which is the distance from the lens to the image and it is f= 195cm

Also,Do is represented by Fe which is 0.52cm and it is the distance of the object to the lens.

Thus m = - f/fe = - 195/0.52 = - 375

6 0

4 years ago

A proton moves along the x-axis in the laboratory with velocity uy = 0.6c. An observer moves with a velocity of v=0.8c along the

Dima020 [189]

Explanation:

Given that,

Velocity of the proton in lab frame $u_{x} = 0.6c$

Velocity of the observer v= 0.8c

We need to calculate the velocity of the proton with respect to the observer

Using formula of velocity

$u'=\dfrac{v-u_{x}}{1-\dfrac{u_{x}v}{c^2}}$

$u'=\dfrac{0.8c-0.6c}{1-\dfrac{0.6c\times0.8c}{c^2}}$

$u'=c(\dfrac{0.8-0.6}{1-(0.8\times0.6)})$

$u'=0.385c$

(a). We need to calculate the total energy of the proton in the lab frame

Using formula of kinetic energy

$K.E=m_{0}c^2(\dfrac{1}{\sqrt{1-\dfrac{u_{x}^2}{c^2}}}-1)$

Where, Proton mass energy = m₀c²

Put the value into the formula

$K.E=938.28\times(\dfrac{1}{\sqrt{1-\dfrac{(0.6c)^2}{c^2}}}-1)$

$K.E=938.28\times(\dfrac{1}{\sqrt{1-(0.6)^2}}-1)$

$K.E=234.57\ MeV$

(b). We need to calculate the kinetic energy of the proton in the observer

Using formula of kinetic energy

$K.E=m_{0}c^2(\dfrac{1}{\sqrt{1-\dfrac{u'^2}{c^2}}}-1)$

$K.E=938.28\times(\dfrac{1}{\sqrt{1-\dfrac{(0.385)^2}{c^2}}}-1)$

$K.E=938.28\times(\dfrac{1}{\sqrt{1-(0.385)^2}}-1)$

$K.E=78.366\ MeV$

(c). We need to calculate the momentum of the proton with respect to observer

Using formula of momentum

$P_{obs}=\dfrac{m_{0}u'^2}{\sqrt{1-\dfrac{u'^2}{c^2}}}$

We know that,

Proton mass energy = m₀c²

$m_{0}=\dfrac{938.28}{c^2}$

$P_{obs}=\dfrac{\dfrac{938.28}{c^2}\times(0.385c)^2}{\sqrt{1-\dfrac{(0.385c)^2}{c^2}}}$

$P_{obs}=\dfrac{938.28\times(0.385)^2}{\sqrt{1-0.385^2}}$

$P_{obs}=150.69\ MeV/c$

Hence, This is required solution.

3 0

3 years ago