Answer:
B
Explanation:
The electronegativity of an atom is a chemical property of that atom that describes the tendency of the atom in question to attract a lone pair of electrons towards itself.
Across the periods, that is going from left to right on the periodic table, it is expected that there is an increase in the electronegativity of elements. Hence, there are more electronegative elements on the right hand side of the periodic table. Thus, we say chlorine or fluorine is more electronegative than either sodium and magnesium.
While it is expected to increase across the period, electronegativity decreases down the group. Hence, we know that chlorine is more electronegative than bromine while fluorine is more electronegative than chlorine. In fact, fluorine is the most electronegative element as it is the first member of the most electronegative group of elements.
Fluorine and oxygen are expected to undergo a covalent bond formation. Both are electron deficient and thus completes their electron orbits by entering into covalent bonding with each other
Answer:325 mL of acid
Explanation:250 mL + 75 mL = 325 mL
Answer:
1. nitric acid: sa
2. perchloric acid: sa
3. hydrofluoric acid: wa
Explanation:
A strong acid (sa) is the one that is completely dissociated into ions in water. Conversely, a weak acid (wa) is not completely dissociated in water.
From the options, the strong acids are:
1. nitric acid (HNO₃). It dissociates completely into ions when is dissolved in water, as follows:
HNO₃ → H⁺ + NO₃⁻
2. perchloric acid (HClO₄). It is completely dissociated in water as follows:
HClO₄ → H⁺ + ClO₄⁻
The weak acid is hydrofluoric acid (HF). In water, only a small proportion is dissociated into ions. The proportion of ions formed is given by the equilibrium constant Ka. The dissociation is written by using double arrows:
HF ⇄ H⁺ + F⁻
<span>This is rather a case of purification of impure copper or extraction of Cu from its alloy. You need to place the impure copper rod on the positive electrode (Anode) usualyy made of carbon rod, whereby oxidation reaction takes place: Cu (s) -------> Cu2+ (aq) + 2e- That is to say the impure cooper dissolves into solution. The copper (II) ions move to the negative electrode (cathode) usually made of pure copper rod. At the cathode, the Cu2+ ions are reduced : Cu2 (aq)+ + 2e- -----> Cu(s). That is to say the copper (II) ions are deposited as solid copper atoms onto the cu-rod electrode. In this way impure copper is deposited as pure copper onto the copper cathode</span>
I think that they will revolt one another. I am not 100% shure tho
Hope this helps :))
