C, to make sure the design works as expected.
A prototype is first, typical model of the said product. Hope this helps!
Answer:
1.35 g
Explanation:
Data Given:
mass of Potassium Permagnate (KMnO₄) = 3.34 g
Mass of Oxygen: ?
Solution:
First find the percentage composition of Oxygen in Potassium Permagnate (KMnO₄)
So,
Molar Mass of KMnO₄ = 39 + 55 + 4(16)
Molar Mass of KMnO₄ = 158 g/mol
Calculate the mole percent composition of Oxygen in Potassium Permagnate (KMnO₄).
Mass contributed by Oxygen (O) = 4 (16) = 64 g
Since the percentage of compound is 100
So,
Percent of Oxygen (O) = 64 / 158 x 100
Percent of Oxygen (O) = 40.5 %
It means that for ever gram of Potassium Permagnate (KMnO₄) there is 0.405 g of Oxygen (O) is present.
So,
for the 3.34 grams of Potassium Permagnate (KMnO₄) the mass of Oxygen will be
mass of Oxygen (O) = 0.405 x 3.34 g
mass of Oxygen (O) = 1.35 g
SrCl2 + Li2(SO4) —> 2LiCl + Sr(SO4)
Kansas City, Missouri, is often abbreviated as KC (abbreviations often refer to the metro area). It is officially nicknamed the City of Fountains. With over 200 fountains, the city claims to have the second most in the world, just behind Rome.
I will use this conversion:
1m = 1000 mm => 1 = 1m / 1000mm
1 m = 100 cm=> 1 = 1m / 100cm
1m = 10 dm=> 1 = 1m / 10 dm
So,
B) 3.8 * 10^7 cm^3 = 3.8 * 10^7 cm^3 * [1m / 100cm]^3 = 38 m^3
C) 3.8 * 10^5 dm^3 * [1m / 10 dm]^3 = 380 m^3
D) 3.8 * 10^8 mm^3 * [1m / 1000 mm]^3 = 0.38 m^3
Now you can compare the four volumes and conclude which is the largest.
Answer: option C) 3.8 * 10^5 dm^3
