2H2O --> 2H2 + O2
The mole H2O:mole O2 ratio is 2:1
Now determine how many moles of O2 are in 50g: 50g × 1mol/32g = 1.56 moles O2
Since 1 mole of O2 was produced for every 2 moles of H2O, we need 2×O2moles = H2O moles
2×1.56 = 3.13 moles H2O
Finally, convert moles to grams for H2O:
3.13moles × 18g/mol = 56.28 g H2O
D) 56.28
<u>Answer:</u> The decreasing order of
is 
<u>Explanation:</u>
The balanced equilibrium reaction for the ionization of silver bromide follows:

s s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Ag^{+}][Br^-]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BAg%5E%7B%2B%7D%5D%5BBr%5E-%5D)
We are given:

Putting values in above equation, we get:

Solubility product of AgBr = 
The balanced equilibrium reaction for the ionization of silver cyanide follows:

s s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Ag^{+}][CN^-]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BAg%5E%7B%2B%7D%5D%5BCN%5E-%5D)
We are given:

Putting values in above equation, we get:

Solubility product of AgCN = 
The balanced equilibrium reaction for the ionization of silver thiocyanate follows:

s s
The expression for solubility constant for this reaction will be:
![K_{sp}=[Ag^{+}][SCN^-]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BAg%5E%7B%2B%7D%5D%5BSCN%5E-%5D)
We are given:

Putting values in above equation, we get:

Solubility product of AgSCN = 
The decreasing order of
follows:

Answer:
H-O
Explanation:
because oxygen and hydrogen have very high difference in electronegativity