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klasskru [66]
3 years ago
6

The ions formed by nonmetals in group 6A and 7A...

Chemistry
1 answer:
allochka39001 [22]3 years ago
4 0

Answer: Option (A) is the correct answer.

Explanation:

A non-metal is a substance which tends to gain electrons from another atom in order to acquire noble gas electronic configuration.

For example, elements of group 6A have 6 valence electrons and elements of group 7A have 7 valence electrons.

Hence, in order to know the charge acquired by the elements of these groups we should subtract their group number from 8.

So, elements of group 6A forms (8 - 6) = 2. That is A^{2-} ion is formed in general.

Similarly, elements of group 7A forms (8 - 7) = 1. That is A^{-1} ion is formed in general.

Thus, we can conclude that the ions formed by non-metals in group 6A and 7A have a numerical charge that is found by subtracting the group number from 8.

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he equation represents the combustion of sucrose. C12H22O11 + 12O2 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of oxy
xeze [42]

Answer:

The moles of sucrose that are available for this reaction is 0.0292 moles

Explanation:

Combustion is an specifyc reaction where the reactants react with O₂ in order to produce CO₂ and H₂O

This combustion is: C₁₂H₂₂O₁₁ + 12O₂  → 12CO₂ + 11H₂O

We have to conver the mass to moles, to find out the limiting reactant

10 g . 1 mol / 342 g = 0.0292 moles of sucrose

8 g . 1mol / 32g = 0.250 moles of O₂

The moles of sucrose that are available for this reaction is 0.0292 moles

Before we start to work with the equation we must find the limiting reactant. When you find it, you can do all the calculations.

6 0
3 years ago
What causes the shielding effect to remain constant across a period?
Ivanshal [37]
Electrons are added to the same principal energy level.
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What is the variable for the equilibrium constant<br><br> Re<br> K<br> Ec<br> E
Nitella [24]

Answer: I am pretty sure it is E

Explanation:

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3 years ago
A flask with a volume of 125.0 mL contains air with a density of 1.298 g/L. what is the mass of the air contained in the flask?
horsena [70]
A flask with a volume of 125.0 mL contains air with a density of 1.298 g/L. what is the mass of the air contained in the flask<span>The given are: </span>
<span><span>1.      </span>Mass = ?</span><span><span /></span>
<span><span>2.      </span>Density = 1298 g/L</span>
3.      Volume = 125mL to L
a. 125 ml x 0.001l/1ml = 0.125 L

<span>Formula and derivation: </span><span><span>
1.      </span>density = mass / volume</span> <span><span>
2.      mass </span>= density / volume</span>

<span>Solution for the problem: </span><span><span>

1. mass = </span></span> <span> 1298 g/L / 0.125 L = 10384g
</span>


8 0
3 years ago
Que enuncia la ley de la conservación de la energia​
Flauer [41]

english:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.

spanish:

En física y química, la ley de conservación de la energía establece que la energía total de un sistema aislado permanece constante; se dice que se conserva con el tiempo.

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