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2 years ago

Please help I need help on this question I have no idea how to do it

Mathematics

1 answer:

Lostsunrise [7]2 years ago

7 0

Enlarge since you looking at the blue lime (B’...)

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Will Mark brainliest if correct.

Serhud [2]

Answer:

SF = 7/3

Step-by-step explanation:

Like the problem hint says, you want to put the new coordinate over the old one to find the scale factor. We'll use both x and y.

-7/-3 = 7/3

14/6 = 7/3

Therefore, the scale factor is 7/3.

4 0

3 years ago

A family pass to the amusement park costs $54 Using the Distributive Property,write an expression that can be used to fine the c

ruslelena [56]

<span>The distributive property is: a(b + c) = ab + ac. In this expression, the example would be 8(54 + 0) = (8 x 54) + (8 x 0). The cost of eight family passes is therefore equal to 8 x 54. $432 is the answer.</span>

8 0

3 years ago

HHEEEEEEELPPPPP, I'LL MARK THE BRAINLIEST

navik [9.2K]

Answer: 6 square 4

Step-by-step explanation:

i hope this helps

7 0

3 years ago

Read 2 more answers

A survey of 132 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take

ddd [48]

Answer:

For 90% CI = (0.428, 0.572)

For 98% CI = (0.399, 0.601)

The confidence interval (and Margin of error) reduces when 90% confidence level is used compared to when 98% confidence level is used.

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

p+/-z√(p(1-p)/n)

Given that;

Proportion p = 66/132 = 0.50

Number of samples n = 132

Confidence level = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

0.50 +/- 1.645√(0.50(1-0.50)/132)

0.50 +/- 1.645√(0.001893939393)

0.50 +/- 0.071589436011

0.50 +/- 0.072

(0.428, 0.572)

The 90% confidence level estimate of the true population proportion of students who responded "yes" is (0.428, 0.572)

For 90% CI = (0.428, 0.572)

For 98% CI = (0.399, 0.601)

The confidence interval (and Margin of error) reduces when 90% confidence level is used compared to when 98% confidence level is used.

7 0

3 years ago

Christine performed the following experiment 20 times using a book that contains 462 pages.

wel

Using the probability concept, it is found that there is a 0.3 = 30% experimental probability that Christine will randomly choose a page that is divisible by 3.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In an experimental probability, these number of outcomes are taken from previous trials.

In this problem:

The experiment was made 20 times.

Of those, in 6 experiments(81, 105, 171, 159, 297, 387) she choose a page that was divisible by 3.

Then:

$p = \frac{6}{20} = 0.3$

0.3 = 30% experimental probability that Christine will randomly choose a page that is divisible by 3.

You can learn more about the probability concept at brainly.com/question/15536019

7 0

2 years ago