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Artemon [7]
3 years ago
15

A job placement agency helps match job seekers with potential employers. The agency would like to design a simulation in order t

o help predict the likely job placement outcomes for job seekers based on historical trends and patterns. Which of the following is most likely to be a benefit of the simulation?
A. The computer simulation will be able to include more details and complexity than the real-world job placement process.
B. The computer simulation could be used to test hypotheses about patterns in the job placement process that are costly or time consuming to observe in reality.
C. The computer simulation will be able to precisely predict the real-world outcomes for each job seeker.
D. The computer simulation will remove the bias that may arise in the real-world job placement process.
Computers and Technology
1 answer:
g100num [7]3 years ago
5 0

Answer:

B

Explanation:

The point of simulating would be to eliminate the part of having to go through un patential applications and save time.

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Answer:

#include<iostream>

#include<stdlib.h>

using namespace std;

int main(){

   //initialization

   string str1[5];

   int arr_Vote[5];

   int Total_Vote=0,max1_Index;

   int max1=INT_MIN;

   //loop for storing input enter by user

   for(int i=0;i<5;i++){

       cout<<"Enter the last name of candidate: "<<endl;

       cin>>str1[i];

       cout<<"Enter the number of vote receive by the candidate: "<<endl;

       cin>>arr_Vote[i];

       //calculate the sum

       Total_Vote = Total_Vote + arr_Vote[i];

       //find the index of maximum vote

       if(arr_Vote[i]>max1){

           max1=arr_Vote[i];

           max1_Index=i;

       }

   }

   //display

   cout<<"\nThe output is......"<<endl;

   //loop for display data of each candidate

   for(int i=0;i<5;i++){

       cout<<str1[i]<<"\t"<<arr_Vote[i]<<"\t"     <<float(arr_Vote[i]*100)/Total_Vote<<"%"<<endl;

   }

   //display winner

   cout<<"The winner candidate is"<<endl;

   cout<<str1[max1_Index]<<"\t"<<arr_Vote[max1_Index]<<"\t"<<float(arr_Vote[max1_Index]*100)/Total_Vote<<" %"<<endl;

}

Explanation:

Create the main function and declare the two arrays and variables.

the first array for storing the names, so it must be a string type. second array stores the votes, so it must be int type.

after that, take a for loop and it runs for 5 times and storing the values entered by the user in the arrays.

we also calculate the sum by adding the array data one by one.

In the same loop, we also find the index of the maximum vote. take an if statement and it checks the element in the array is greater than the max1 variable. Max1 variable contains the very small value INT_MIN.

If condition true, update the max1 value and update the max1_Index value.

The above process continues for each candidate for 5 times.

After that, take a for loop and display the data along with percentage by using the formula:

Vote\,percent=\frac{Vote\,receive*100}{Total\,vote}

the, finally display the winner by using the max1_Index value.  

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I have six nuts and six bolts. Exactly one nut goes with each bolt. The nuts are all different sizes, but it’s hard to compare t
juin [17]

Answer:

Explanation:

In order to arrange the corresponding nuts and bolts in order using quicksort algorithm, we need to first create two arrays , one for nuts and another for bolts namely nutsArr[6] and boltsArr[6]. Now, using one of the bolts as pivot, we can rearrange the nuts in the nuts array such that the nuts on left side of the element chosen (i.e, the ith element indexed as nutArr[i]) are smaller than the nut at ith position and nuts to the right side of nutsArr[i] are larger than the nut at position "I". We implement this strategy recursively to sort the nuts array. The reason that we need to use bolts for sorting nuts is that nuts are not comparable among themselves and bolts are not comparable among themselves(as mentioned in the question)

The pseudocode for the given problem goes as follows:

// method to quick sort the elements in the two arrays

quickSort(nutsArr[start...end], boltsArr[start...end]): if start < end: // choose a nut from nutsArr at random randElement = nutsArr[random(start, end+1)] // partition the boltsArr using the randElement random pivot pivot = partition(boltsArr[start...end], randElement) // partition nutsArr around the bolt at the pivot position partition(nutsArr[start...end], boltsArr[pivot]) // call quickSort by passing first partition quickSort(nutsArr[start...pivot-1], boltsArr[start...pivot-1]) // call quickSort by passing second partition quickSort(nutsArr[pivot+1...end], boltsArr[pivot+1...end])

// method to partition the array passed as parameter, it also takes pivot as parameter

partition(character array, integer start, integer end, character pivot)

{

       integer i = start;

loop from j = start to j < end

       {

check if array[j] < pivot

{

swap (array[i],array[j])

               increase i by 1;

           }

 else check if array[j] = pivot

{

               swap (array[end],array[j])

               decrease i by 1;

           }

       }

swap (array[i] , array[end])

       return partition index i;

}

7 0
3 years ago
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