We are to solve the total area of the pyramid and this can be done through area addition. We first determine the area of the base using the Heron's formula.
A = √(s)(s - a)(s - b)(s - c)
where s is the semi-perimeter
s = (a + b + c) / 2
Substituting for the base,
s = (12 + 12 + 12)/ 2 = 18
A = (√(18)(18 - 12)(18 - 12)(18 - 12) = 62.35
Then, we note that the faces are just the same, so one of these will have an area of,
s = (10 + 10 + 12) / 2 = 16
A = √(16)(16 - 12)(16 - 10)(16 - 10) = 48
Multiplying this by 3 (because there are 3 faces with these dimensions, we get 144. Finally, adding the area of the base,
total area = 144 + 62.35 = 206.35
<span>Any number raised to the zero power equal to one
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HEY MATE HERE IS YOUR ANSWER.
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if we're factoring you can use the AC method. A multiplied by C is 24. and 4x6 is 24.
(x+4)(x+6) is your answer
Answer:
<em>B. (U+V)(U-V)</em>
Step-by-step explanation:
<u>Factoring</u>
The given expression is:
It should be noted that both terms are perfect squares:
Since it's a difference of squares, we need to use the following pattern to factor the required expression:
Thus, the answer is
B. (U+V)(U-V)