The answer to this question is 722,357,000
Consider two adjacent rectangular rooms having Length=L, and, Breadth = B
Now Suppose the wall which is in between two rooms has a height or length =H.
Breadth of wall = B [ if the wall doesn't exceed the breadth of room]
Considering two rooms to be identical,
Area of each room= L × B square unit
Area of each tile = 1×1=1 square unit
Number of tiles required= L B ÷ 1= LB tiles( product of length and breadth of room is number of tiles required)
Suppose if,LB= N
B= N/L .................(1)
Area of wall(W) = B×H= B H square unit
B =W/H ......................(2)
Equating (1) and (2)
⇒N/L = W/ H
⇒H =w-z/N
⇒H =WL/LH
⇒H = W/B
⇒ H =area of wall / Breadth of room and wall
Interchange the x and y and solve for the resulting y.
x = 4y^2 - 2
(x + 2) = 4y^2
(x + 2)/4 = y^2
+/- sqrt(x + 2)/2 = y
The graph of these two is below.
The original is in red
The inverse is in blue and green
Answer:
8
Step-by-step explanation:
Because it is equal to the 4 side
<h3>
Geometric sequence.</h3>
A geometric sequence goes from one term to the next by always multiplying or dividing by the constant value except 0. The constant number multiplied (or divided) at each stage of a geometric sequence is called the common ratio (r).
We have:
Find the common ratio:
<h3>The formula of the n-th term of a geometric sequence:</h3>
Substitute:
<h3>Method step by step:</h3>