The terms in which value of x when substituted leaves final value of p(x) = "0".
Here, x - 2 is factor. So value of x is 2.
Substituting value of x we get,
p(x) = x3 - 3x + 5a
p(2) = 2*3 - 3(2) + 5a
0+ 8-6 + 5a
-2 = 5a
a= -0.4
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Answer:
<em><u>Option A </u></em>will be your answer
Step-by-step explanation:
<em><u>hope it helps </u></em><em><u>.</u></em><em><u>.</u></em>
<em><u>have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>great</u></em><em><u> </u></em><em><u>day</u></em><em><u>!</u></em><em><u>!</u></em>
Answer:
D.
Step-by-step explanation:
In order to eliminate, the numbers must eliminate. If the second equation is multiplied by 3, then the 3 and the -3 can be eliminated. Since it is multiple choice, we can plug in x = 12 and y = 10 to see if they are correct. 12 + 30 = 42 and 24 - 10 = 14, so D is correct.
D because it is a decline and they are loosing 75% of their jobs
