Fide f (-4) evaluate the function
1 answer:
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Answer:
4.9%
Step-by-step explanation:
This question is incomplete. However; it can be found on search engines. The complete question is as follows :
An ice chest contains cans of six apple juice, eight cans of grape juice, four cans of orange juice, and two cans of mango juice. Suppose that you reach into the container and randomly select three cans in succession. Find the probability of selecting three cans of grape juice.
Solution :
In an ice chest there are different cans of juice. Among them
Number of cans of apple juice = 6
Number of cans of grape juice = 8
Number of cans of orange juice = 4
Number of cans of mango juice = 2
Total number of cans of juice = 6 + 8 + 4 + 2 = 20
Let A, B and C are the event of selecting of three cans. The events A, B and C are dependent.
Probability of selecting three cans of juice
P =
P (A) =
P (B) =
P (B) =
P = ×
×
=
= 0.049 or 4.9%
Probability of selecting three cans of grape juice is 4.9%