1. The mass of 1.33×10²² mole of Sb is 1.62×10²⁴ g
2. The mass of 4.75×10¹⁴ mole of Pt is 9.26×10¹⁶ g
3. The mass of 1.22×10²³ mole of Ag is 1.32×10²⁵ g
4. The mass of 9.85×10²⁴ mole of Cr is 5.12×10²⁶ g
<h3>1. Determination of the mass of 1.33×10²² mole of Sb</h3>
- Mole of Sb = 1.33×10²² mole
- Molar mass of Sb = 122 g/mol
Mass = mole × molar mass
Mass of Sb = 1.33×10²² × 122
Mass of Sb = 1.62×10²⁴ g
<h3>2. Determination of the mass of 4.75×10¹⁴ mole of Pt</h3>
- Mole of Pt = 4.75×10¹⁴ mole
- Molar mass of Pt = 122 g/mol
Mass = mole × molar mass
Mass of Pt = 4.75×10¹⁴ × 195
Mass of Pt = 9.26×10¹⁶ g
<h3>3. Determination of the mass of 1.22×10²³ mole of Ag</h3>
- Mole of Ag = 1.22×10²³ mole
- Molar mass of Ag = 108 g/mol
Mass = mole × molar mass
Mass of Ag = 1.22×10²³ × 108
Mass of Ag = 1.32×10²⁵ g
<h3>4. Determination of the mass of 9.85×10²⁴ mole of Cr</h3>
- Mole of Cr = 9.85×10²⁴ mole
- Molar mass of Cr = 52 g/mol
Mass = mole × molar mass
Mass of Cr = 9.85×10²⁴ × 52
Mass of Cr = 5.12×10²⁶ g
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Answer:
[ HClO₃] = 1.93M
Explanation:
X % by mass, means that in 100 g of solution, we have X g of solute.
In this case, 14.1 g of HClO₃ are contained in 100 g of solution.
Density always referrs to solution. Let's calculate the volume of solution.
Solution density = Solution mass / Solution volume
1.1690 g/mL = 100 g / Solution volume
Solution volume = 100 g /1.1690 g/mL → 86.2 mL.
For molarity we must get moles of solute and volume of solution (L), because molarity is mol/L
Let's convert the mL of solution in L
86.2 mL . 1L / 1000mL = 0.0862 L
Now, let's determine the moles of solute. (Mass / Molar mass)
14.1 g / 84.45 g/mol = 0.167 moles
Molarity is mol/L → 0.167 moles / 0.0862 L = 1.93M
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