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mihalych1998 [28]
3 years ago
15

What does an atom become if it gains or loses electrons?

Chemistry
1 answer:
Tju [1.3M]3 years ago
3 0
I think a is the answerr
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175 mL of a 1.6 M solution of KCl is diluted to a new volume of 1.0 L. What is the new concentration of the solution?
kupik [55]

Answer:

b. .28 M KCI

Explanation:

Use the dilution formula.

C₁V₁ = C₂V₂

C₂ = C₁V₁/V₂

C₂ = 1.6*0.175 / 1.0

C₂ = 0.28

6 0
2 years ago
Sodium tert-butoxide (NaOC(CH3)3) is classified as bulky and acts as Bronsted Lowry base in the reaction. It is reacted with 2-c
IceJOKER [234]

Answer:but-1-ene

Explanation:This is an E2 elimination reaction .

Kindly refer the attachment for complete reaction and products.

Sodium tert-butoxide is a bulky base and hence cannot approach the substrate 2-chlorobutane from the more substituted end and hence major product formed here would not be following zaitsev rule of elimination reaction.

Sodium tert-butoxide would approach from the less hindered side that is through the primary centre and hence would lead to the formation of 1-butene .The major product formed in this reaction would be 1-butene .

As the mechanism of the reaction is E-2 so it will be a concerted mechanism and as sodium tert-butoxide will start abstracting the primary hydrogen through the less hindered side simultaneously chlorine will start leaving. As the steric repulsion in this case is less hence the transition state is relatively stabilised and leads to the formation of a kinetic product 1-butene.

Kinetic product are formed when reactions are dependent upon rate and not on thermodynamical stability.

2-butene is more thermodynamically6 stable as compared to 1-butene  

The major product formed does not follow the zaitsev rule of forming a more substituted alkene as sodium tert-butoxide cannot approach to abstract the secondary proton due to steric hindrance.

5 0
3 years ago
Consider the reaction between acetylene, c2h2, and oxygen in a welding torch: 2c2h2(g) + 5o2(g) → 4co2(g) + 2h2o(g) if 5.4 moles
fredd [130]
<span>                                      2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
   from the reaction     2 mol                              4 mol
from the problem      5.4 mol                         10.8 mol

M(CO2) = 12.0 +2*16.0 = 44.0 g/mol
10.8 mol CO2 * 44.0 g CO2/1 mol CO2 = 475.2 g CO2 </span>≈480 = 4.8 * 10² g
Answer is  C. 4.8*10² g.
4 0
3 years ago
Read 2 more answers
A solution of hydrochloric acid (HCl, 25.00 mL) was titrated to completion with 34.55 mL of 0.1020 M sodium hydroxide. What was
kati45 [8]

Answer:

0.1410 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 1

The mole ratio of the base, NaOH (nB) = 1

Next, the data obtained from the question. This include:

Volume of acid, HCl (Va) = 25 mL

Volume of base, NaOH (Vb) = 34.55 mL

Concentration of base, NaOH (Cb) = 0.1020 M

Concentration of acid, HCl (Ca) =?

CaVa / CbVb = nA/nB

Ca × 25 / 0.1020 × 34.55 = 1/1

Ca × 25 / 3.5241 = 1/1

Cross multiply

Ca × 25 = 3.5241 × 1

Ca × 25 = 3.5241

Divide both side by 25

Ca = 3.5241 / 25

Ca = 0.1410 M

Therefore, the concentration of the acid, HCl is 0.1410 M

3 0
3 years ago
Please help soon!!! About Chemistry and noble gas notations.
Svetach [21]

Answer:

play video games all days

Explanation:

ggggggggghahahahahahaha

8 0
2 years ago
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