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makvit [3.9K]
3 years ago
14

11. Calculate the amount of heat transferred when 550 grams of water cools from an initial temperature of

Chemistry
1 answer:
Reptile [31]3 years ago
3 0

Answer:

–48.3 KJ

Explanation:

Data obtained from the question. This includes the following:

Mass (M) = 550g

Initial temperature (T1) = 25°C

Final temperature (T2) = 4°C

Change in temperature (ΔT) = T2 – T1 = 4°C – 25°C = –21°C

Specific heat capacity (C) = 4.184J/g°C

Heat (Q) =.?

The heat transferred can be obtained as follow:

Q = MCΔT

Q = 550 x 4.184 x –21

Q = – 48325.2 J = –48.3KJ

Therefore, the heat transferred is –48.3KJ since we are cooling the water.

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1. Starting with 9.3 moles of O 2 , how many moles of H 2 S will be needed and how many moles of SO 2 will
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Answer:

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Moles of SO₂ produced = ?

Solution:

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                  O₂             :           H₂S

                    3             :             2

                   9.3            :         2/3×9.3 = 6.2 mol

Now we will compare the moles of SO₂ with both reactant.

                   O₂             :            SO₂

                    3              :               2

                   9.3            :         2/3×9.3 = 6.2 mol      

                 H₂S             :            SO₂

                    2              :               2

                   6.2            :          6.2 mol      

So 6.2 moles of  SO₂ are produced.

         

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