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MAXImum [283]
3 years ago
6

Put these fractions in ascending order 1/2 3/5 and 3/4 ​

Mathematics
1 answer:
MAXImum [283]3 years ago
7 0
1/2=50/100 then 3/5=60/100 and finally 3/4=75/100 so the order is 1/2,3/5,3/4
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What is the sum of the arithmetic sequence 151, 137, 123,..if there are 26 terms?
ElenaW [278]
First term: a1 = 151
common difference: d = -14 (we decrease by 14 each time, eg, 151-14 = 137)

nth term of this arithmetic sequence is...
an = a1+d(n-1)
an = 151+(-14)(n-1)
an = 151-14n+14
an = -14n+165

This will be used in the formula below

Sn = n*(a1+an)/2
<span>Sn = n*(151+(-14n+165))/2
</span><span>S26 = 26*(151+(-14*26+165))/2 ... replace every n with 26
</span>S26 = -624

The final answer here is choice C) -624
<span>
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5 0
3 years ago
Plz help me I will give you a brainest​
Lady bird [3.3K]

Answer: −2.4f − 22

Step-by-step explanation: simply combine like terms. -2.7f + .3f would be -2.4f, and -14 - 8 is -22.

4 0
3 years ago
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G is between F and H, FG = 8, and FH = 12.<br> Find GH.<br> O GH= 4<br> O GH = 12<br> O GH = 5
ANEK [815]

Answer:

GH = 4

Step-by-step explanation:

Since G is between F and H then

FG + GH = FH , that is

8 + GH = 12 ( subtract 8 from both sides )

GH = 4

5 0
3 years ago
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Identify all factors of the expression 12x^2-14x-6
Evgen [1.6K]

Let's solve this by using the quadratic formula:

\frac{-b+-\sqrt{b^2-4ac} }{2a}


Note that we only use the coefficients so a=12, b=-14, and c=-6.

Plug values in the quadratic equation:

\frac{ -  ( - 14)± \sqrt{ {( - 14)}^{2} - 4(12)( - 6) } }{2(12)}

And so by evaluating those values we obtain:

\frac{14+-\sqrt{484} }{24}=\frac{14+-22}{24}  \\\\

Now we have two answers which are our factors one where we add another where we subtract and so:

First factor:

\frac{14+22}{24}=\frac{36}{24}=\frac{3}{2}


Second Factor:

\frac{14-22}{24}=\frac{-8}{24}=-\frac{1}{3}


And so your factors are

\frac{3}{2},-\frac{1}{3}

meaning that those are your roots/x-intercepts.


6 0
3 years ago
If a single one of these can be answered, can someone help me? I put my book somewhere. I’ll mark brainliest to actual answers :
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