The energy transferred on the object is 1000 Joules.
Given:
An object on which a constant force of 100 N was applied to displace it over a distance of 10 meters.
To find:
The energy transfer occurs on the object.
Solution
The force applied on the object = F = 100 N
The displacement of the object = d = 10 m
The energy transferred on the object or work done is given by:
The energy transferred on the object is 1000 Joules.
Learn more about work done here:
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Answer: 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.
Explanation:
According to the dilution law,
where,
= concentration of ist disinfectant solution = 16 %
= volume of pure acid solution = x gallons
= concentration of another disinfectant solution= 23%
= volume of another acid solution= (28-x) gallons
= concentration of resulting disinfectant solution = 18 %
= volume of resulting acid solution = 28 gallons
(28-x) = (28-20) = 8 gallons
Thus 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.
RIVER CAPTURE. *is when the powerful and energetic river cuts back through watershed by headward erosion cupturing another river's water. CONDITION FOR RIVER CAPTURE TO OCCUR. * steeper gradient on the energetic stream side of the watershed.Apr 6, 2019
Answer:
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
Explanation:
Given
1) NO(g) + Cl2(g) → NOCl2(g)
2) NOCl2(g) + NO(g) → 2NOCl(g)
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
k1= [NOCl2]
k-1= [NO] [Cl2]
k2 = [NOCl2] [NO]
Equilibrium for the first equation (reaction 1)
K= k1/k-1 = [NOCl2]/[NO] [Cl2]
Therefore
[NOCl2] = k1/k-1 [NO] [Cl2]
Rate= k2× k1/k-1 [NO]^2 [Cl2]
Rate = Koverall [NO]^2 [Cl2]
Where Koverall= k1k2/k-1
