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professor190 [17]
3 years ago
7

What is the physical state of the products in MgCl2(aq)+2Na(s) -> 2NaCl(aq)+Mg(s)

Chemistry
2 answers:
Neporo4naja [7]3 years ago
7 0
What she had said up above , hope you have a great tomorrow love<33
Degger [83]3 years ago
3 0

Answer:

In your example, sodium reacts with magnesium chloride in a single displacement reaction.

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CaBr2
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Which of the following means a natural occurring solid that has a specific chemical makeup?
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The answer is: A rock
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In the reaction between CH3CH2CH2CH2Cl and CH3ONa, the organic product is
Reptile [31]

The product of the reaction as it has been shown above is  butoxymethane.

<h3>What is a chemical reaction?</h3>

A chemical reaction is an interaction that takes place between two or more chemical substances to yield a product (s). We should note that the reactants are written at the left hand side of the reaction equation while the products are written at the right hand side of the reaction equation. This is how we show  reaction on paper.

Having said this, the reaction that have been shown in the question would occur by an SN2 synchronous mechanism to yield butoxy methane product.

Learn more about reaction:brainly.com/question/14080839

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6 0
1 year ago
In the haber process, ammonia is synthesized from nitrogen and hydrogen: n2 (g) + 3 h2 (g) ? 2 nh3 (g) ?g° at 298 k for this rea
Lera25 [3.4K]
Gibb's free energy, ΔG°, is related to the equilibrium constant of the reaction, K, through the equation:

ΔG°= RT(ln K)

By definition, K is the ratio of the equilibrium partial pressure of the products to the reactants, raised to the power of their stoichiometric coefficients, respectively. For this reaction,

N₂ (g) + 3 H₂ (g) → 2 NH₃<span> (g) 

the equilibrium constant is 

K = [NH</span>₃]²/[N₂][H₂]³

Assuming that the given partial pressures are the equilibrium pressures, then we can substitute them directly:

K = [0.65 atm]²/[1.9 atm][1.6 atm]³
K = 0.05429 atm⁻²

Then, we can using this value to find ΔG. Note that R is the gas constant equal to 0.08206 L-atm/mol-K.

ΔG°= (0.08206 L-atm/mol-K)(298 K)(ln 0.05429 atm⁻²)
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7 0
3 years ago
50 J of work was done on a system, as a result of which 29 J of heat energy was removed from it. How would this affect the inter
Harman [31]

Work done=50J

Heat removed=29J

Now

\\ \sf\longmapsto \Delta E=50-29

\\ \sf\longmapsto \Delta E=21J

Hence the internal energy would increase by 21J

Option B s correct

4 0
3 years ago
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