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2 years ago

What is the physical state of the products in MgCl2(aq)+2Na(s) -> 2NaCl(aq)+Mg(s)

Chemistry

2 answers:

Neporo4naja [7]2 years ago

7 0

What she had said up above , hope you have a great tomorrow love<33

Degger [83]2 years ago

3 0

Answer:

In your example, sodium reacts with magnesium chloride in a single displacement reaction.

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Calculate the change in pH of a 1.00 L of a buffered solution preparing by mixing 0.50 M acetic acid (Ka = 1.8 x 10^-5) and 0.50

tankabanditka [31]

The change in pH of a 1.00 L of a buffered solution preparing by mixing 0.50 M acetic acid (Ka = 1.8 x 10^-5) and 0.50 M sodium acetate when 0.010 mole of NaOH is added is 4.75

when the same amount 0.010 mole of NaOH was added to 1.00 L of water the pH = 12

Explanation:

given that:

concentration of acetic acid = 0.50 M

Concentration of base sodium acetate = 0.50 M

ka = 1.8 x 10^-5)

pka = -log [ka]

pka = 4.74

From Henderson-Hasselbalch Equation:

pH = pKa + log $\frac{[base]}{[acid]}$

pH = 4.74 + Log $\frac{[0.5]}{[0.5]}$

pH = 4.74 + 0

pH = 4.74

Number of moles of NaOH = 0.010 moles

volume 1 litre

molarity = 0.010 M

Moles of acetic acid and sodium acetate before addition of NaOH

FORMULA USED:

molarity = $\frac{number of moles}{volume in litres}$

acetic acid,

0.5 = number of moles

0.5 is the number of moles of sodium acetate.

number of moles of NaOH 0.010 moles

NaOH reacts in 1:1 molar ratio with acetic acid so

number of moles in acetic acid = 0.5 - 0.010 = 0.49

number of moles in sodium acetate = 0.5 +0.010 = 0.51

new pH

pH = pKa + log $\frac{[base]}{[acid]}$

pH= 4.74 + log[0.51] - log[0.49]

pH= 4.75

PH of NaOH of 0.01 M (BASE)

pOH = -Log[0.01]

pOH = 2

pH can be calculated as

14= pH +pOH

pH= 14-2

pH = 12

8 0

3 years ago

Question number 10 & 11, answer please and thank you

nika2105 [10]

Answer:

molarity = moles of solution/liters of solution

molarity = 1 mole/2 liters

molarity = 0.5 M

molarity = 50 moles/200 kg

molarity = 0.25 M

Explanation:

3 0

3 years ago

Which of the following statement explains how fossils can be useful?

Ratling [72]

dihwihdiwhdiwdhiwdhiwhdiwhdiwddiwondwwwwddddddddddddddddddddddddddddddddddwwww

Explanation:

7 0

3 years ago

Determine the moles of H+ reacting with the metal based on the following experimental data. 10.00 mL of 1.00 M HCl solution is a

musickatia [10]

Answer:

Approximately $1.876 \times 10^{-3}\; \rm mol$ .

Explanation:

Convert both volumes to standard units (that is: liters.)

$10.00 \; \rm mL = 10.00 \times 10^{-3}\; \rm L = 1.000 \times 10^{-2}\; \rm L$ .
$27.08 \; \rm mL = 27.08 \times 10^{-3}\; \rm L = 2.708 \times 10^{-2}\; \rm L$ .

Number of moles of $\rm HCl$ initially present (in the $10.00\; \rm mL$ solution at $1.00\; \rm M$ .)

$n(\mathrm{HCl}, \, \text{initial}) = \displaystyle c \cdot V = 1.00\times 1.000 \times 10^{-2}= 1.000\times 10^{-2}\; \rm mol$ .

Number of moles of $\rm NaOH$ from the titration:

$n(\mathrm{NaOH}) = c \cdot V = 0.30 \times 2.708 \times 10^{-2} = 8.124 \times 10^{-3}\; \rm mol$ .

$\rm NaOH$ neutralizes $\rm HCl$ at a $1:1$ ratio:

$\rm HCl + NaOH \to NaCl + H_2O$ .

Hence, $n(\mathrm{HCl},\, \text{leftover}) = n(\mathrm{NaOH}) = 8.124 \times 10^{-3}\; \rm mol$ .

$\begin{aligned}&n(\mathrm{HCl},\, \text{consumed}) \\ =& n(\mathrm{HCl},\, \text{initial}) - n(\mathrm{HCl},\, \text{leftover}) \\ =& 1.000\times 10^{-2} - 8.124\times 10^{-3} \\ =& 1.876 \times 10^{-3}\; \rm mol\end{aligned}$ .

3 0

3 years ago

Xelga [282]

Answer:

Modern periodic law

Explanation:

There are many ways of stating the modern periodic law. Generally, the modern periodic law states that the properties of elements are a periodic function of their atomic numbers. That means, similar properties recur periodically when elements are arranged according to increasing atomic number.

Two scientists were largely responsible for our present day understanding of the modern periodic law, they are, Mendeleev and Moseley. Their work laid the foundation for the periodic table in its current form.

3 0

3 years ago