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Karolina [17]
3 years ago
14

Clathrate hydrate research is done by Professor Kend Janda at UC Irvine. Look up clathrate hydrate with a general internet searc

h and in Odyssey (Applied Chemistry, #86 Clathrates). The ethyl (CH3CH2 –) end of the ethanol molecule (CH3CH2OH) is behaving much like the propane (CH3CH2CH3) and methane (CH4) gases that Prof. Janda\'s group uses to form clathrates. These hydrocarbons (propane, methane, and ethyl) are all nonpolar and, therefore, do not contain any significant dipoles. The _________________ creates a cage where the water is the _________________ for/of the hydrocarbon.
Chemistry
1 answer:
lidiya [134]3 years ago
3 0

Answer:

water, host

Explanation:

Clathrate hydrates are the crystalline water-based solids which physically resembles with the ice, in which the small non-polar molecules or smaller polar molecules with the large hydrophobic moieties are usually trapped inside the "cages" of the hydrogen bonded as well as frozen water molecules.  

<u>Clathrate hydrates are the clathrate compounds in which water creates the cage and the water behaves as a host molecule and guest molecule is typically a gas or liquid.</u>

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Would nitrogen gas be a mineral if it has a chemical formula of n2?
STALIN [3.7K]

<u>Answer:</u>

Nitrogen gas be a mineral only, if it is in organic forms.

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Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

6 0
4 years ago
Which incorrect aspect of Rutherford’s model was fixed by Bohr’s model?
dolphi86 [110]

Answer:

Some things that were wrong with Rutherford's model were that the orbiting electrons should give off energy and eventually spiral down into the nucleus, making the atom collapse. Bohr proposed his quantized shell model of the atom to explain how electrons can have stable orbits around the nucleus. To remedy the stability problem, Bohr modified the Rutherford model by requiring that the electrons move in orbits of fixed size and energy.

Explanation:

7 0
3 years ago
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