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nirvana33 [79]
3 years ago
5

How many minerals are found in earths crust ?

Physics
2 answers:
Damm [24]3 years ago
5 0
You can find your answer here www.rsc.org/education/teachers/resources/jesei/minerals/students.htm
tensa zangetsu [6.8K]3 years ago
3 0
8 i think....................
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For the meter stick shown in figure 10-4, the force F1 10.0 N acts at 10.0 cm. What is the magnitude of torque due to F1 about a
Phantasy [73]

Torque is equal position vector times (r) times force vector (F).  Since F= 10 N and r = 0.1 m, so the torque is equal to (10 N) x ( 0.1 m) = 1Nm. The direction of the torque would be into the screen, clockwise rotation.

8 0
3 years ago
A crate of mass 10.0 kg is pulled up a rough incline with an initial speed of 1.50m/s . The pulling force is 100 N parallel to t
sergey [27]

167.67 Joules of work are done by the gravitational force on the crate.

Force is defined as the product of the mass of the object and acceleration. The SI unit of the force of Newton.

Gravitational force is the force applied by gravity on an object. The gravity of the earth is 9.8 m/s².

Force = Mass × Acceleration

F = m × a

Mass of the crate = 10 kg

The initial speed of the crate = 1.50 m/s

The pulling force = 100 N

Horizontal angle made by the crate = 20 °

Coefficient of kinetic friction = 0.400

The crate is pulled to a height of 5 m.

Sin θ= \frac{height}{distance}

= \frac{h}{d}

h = dSin θ

Work done by the gravitational force on the crate is,

Work done by gravitational force = mass × gravity × height

W_{g} = mgh

W_{g}  = m  \times  g \times d \times sinθ

= 10 \times 9.8 \times 5 \times sin20°

= 167.67 \: J

Therefore, 167.67 Joules of work is done by the gravitational force on the crate.

To know more about force, refer to the below link:

brainly.com/question/13191643

#SPJ4

5 0
2 years ago
Physics // how i solve?
Alex

V=IR

180mA=V/R

I=2V/3R

I=2/3 x 180 mA =120 mA

7 0
3 years ago
A thin rod of length 0.75 m and mass 0.42 kg is suspended freely from one end. It is pulled to one side and then allowed to swin
Goshia [24]

Answer:

(A) 0.63 J  

(B) 0.15 m

Explanation:

length (L) = 0.75 m

mass (m) =0.42 kg

angular speed (ω) = 4 rad/s

To solve the questions (a) and (b) we first need to calculate the rotational inertia of the rod (I)

I = Ic + mh^{2}  

Ic is the rotational inertia of the rod about an axis passing trough its centre of mass and parallel to the rotational axis

h is the horizontal distance between the center of mass and the rotational axis of the rod

I = (\frac{1}{12})(mL^{2} ) + m([tex]\frac{L}{2})^{2}[/tex]

I = (\frac{1}{12})(0.42 x 0.75^{2} ) + ( 0.42 x ([tex]\frac{0.75}{2})^{2}[/tex])

I = 0.07875 kg.m^{2}

(A) rods kinetic energy = 0.5Iω^{2}

  = 0.5 x 0.07875 x 4^{2} = 0.63 J   0.15 m

(B) from the conservation of energy

   initial kinetic energy + initial potential energy = final kinetic energy + final potential energy

   Ki + Ui = Kf + Uf

   at the maximum height velocity = 0 therefore final kinetic energy = 0

   Ki + Ui = Uf

   Ki = Uf - Ui

 Ki =  mg(H-h)

where (H-h) = rise in the center of mass

     0.63 = 0.42 x 9.8 x (H-h)

   (H-h) = 0.15 m

6 0
3 years ago
Get it right and win a brilliant
BlackZzzverrR [31]

In Newton's third law, the action and reaction forces D.)act on different objects

Explanation:

Newton's third law of motion states that:

<em>"When an object A exerts a force on object B (action force), then action B exerts an equal and  opposite force (reaction force) on object A"</em>

It is important to note from the statement above that the action force and the reaction force always act on different objects. Let's take an example: a man pushing a box. We have:

  • Action force: the force applied by the man on the box, forward
  • Reaction force: the force applied by the box on the man, backward

As we can see from this example, the action force is applied on the box, while the reaction force is applied on the man: this means that the two forces do not act on the same object. This implies that whenever we draw the free-body diagram of the forces acting on an object, the action and reaction forces never appear in the same diagram, since they act on different objects.

Learn more about Newton's third law of motion:

brainly.com/question/11411375

#LearnwithBrainly

3 0
3 years ago
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