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3 years ago

14

The local school district ordered 755 decks of cards for teachers to use in their math classes. Each deck comes with 52 cards. H

ow many cards are in all of the decks combined?

2 answers:

cupoosta [38]3 years ago

5 0

Answer:

39,260

Step-by-step explanation:

755 * 52 = 39,260

Fantom [35]3 years ago

3 0

Answer:

755x52=39260 fhdhdhdhddddndnd

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5cosx -2sin(x/2) +7=0<br>Help me to find x step by step<br>pls

miskamm [114]

Answer:

x = 180

Step-by-step explanation:

First, you need to know

1. Double-angle formula:

cos(2x) = $cos^{2}x - sin^{2}x$

2. Pythagorean identity:

$cos^{2}x + sin^{2}x = 1$

Back to your problem, replacing the variable by the above:

$5cosx-sin\frac{x}{2}+7 = 0$

$5(cos^{2}\frac{x}{2}-sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0$ By Double-angle formula

$5(1 - 2sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0$ By Pythagorean identity

Given $y = \frac{x}{2}$

$5(1-2sin^{2}y) - 2siny + 7 = 0$

$10sin^{2}y+2siny-12=0$

$5sin^{2}y+siny-6=0$

$(5siny + 6)(siny - 1)=0$ , we know -1 < sinx < 1, for every x ∈ R

$siny = 1, y =90$

$y = \frac{x}{2}$

$x = 180$

8 0

3 years ago

A math test is worth 100 points and has 38 problems. Each problem is worth either 5 points or 2 points. How many problems of eac

Natasha_Volkova [10]

Let x be the number of 5 points question.
Let y be the number of 2 points question.

Total number of questions is 38
x + y = 38

Total points is 100
5x + 2y = 100

x + y = 38 ------------- (1)
5x + 2y = 100 ---------(2)

From (1):
x + y = 38
x = 38 - y -------------- sub into (2)
5(38 - y) + 2y = 100
190 - 5y + 2y = 100
3y = 90
y = 30 ------------------ sub into (1)
x + 30 = 38
x = 38 - 30
x = 8

There are 8 5-point questions and 30 2-point questions

5 0

3 years ago

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If the functions are linear, write than in f(x)= ax+b form.

Norma-Jean [14]

The answer is 2x-8 and 1/7+7

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3 years ago

Which is the approximate solution for the system of equations 3x+4y=2 and 4x+y=-4

harina [27]

$3x+4y=2\qquad\text{subtract 3x from both sides}\\\\4y=-3x+2\qquad\text{divide both sides by 4}\\\\y=-\dfrac{3}{4}x+\dfrac{2}{4}\to y=-\dfrac{3}{4}x+\dfrac{1}{2}\\\\for\ x=0\to y=-\dfrac{3}{4}(0)+\dfrac{1}{2}=0+\dfrac{1}{2}=\dfrac{1}{2}\to\left(0,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=-\dfrac{3}{4}(2)+\dfrac{1}{2}=-\dfrac{3}{2}+\dfrac{1}{2}=-\dfrac{2}{2}=-1\to(2,\ -1)\\--------------------------------\\$

$4x+y=-4\qquad\text{subtract 4x from both sides}\\\\y=-4x-4\\\\for\ x=0\to y=-4(0)-4=0-4=-4\to(0,\ -4)\\\\for\ x=-1\to y=-4(-1)-4=4-4=0\to(-1,\ 0)\\\\Answer:\ \boxed{A.\ (-1.4,\ 1.5)}$

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3 years ago

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Anybody know the answer?

Ulleksa [173]

Answer:

25 yxdyxd7fcc7fc7fcfuufc7cf

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3 years ago