The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
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Answer:
The number is 523
Step-by-step explanation:
<u><em>The question is English is</em></u>
Number 289 less than 812
Let
x ----> the number
To find out the number subtract 289 from 812
so
therefore
The number is 523
Looks like 7 games scored 73 or 74, 1 scored 75 or 76 and 1 scored 77 or 78, so
Answer: 9 games, second choice
Slope = (-12 - 43)/(4 +7) = -55/11 = -5
y = mx + b
43 = -5(-7) + b
43=35+b
b = 8
equation
y = -5x + 8
