Answer:
The integers are "closed" under addition, multiplication and subtraction, ... The rational numbers are "closed" under addition, subtraction, and multiplication
Step-by-step explanation:
The blank spaces about the passage can be filled with the following correct vocabulary respectively.
- inequality
- strict inequality
- compound inequality
- solution sets
- true
<h3>Inequality</h3>
An <u>inequality</u> is a relation between two numbers and/or expressions that are related via <, >, ≥ or ≤ sign.
A <u>strict inequality</u> is an expression that uses < and >. It tells us that one side is only more or less than the other side.
When 2 simple inequalities are joined by or and, we get a <u>compound inequality</u>.
When solving an inequality, the solution will be a range of values called its <u>solution sets</u>. The inequality will remain <u>true</u> for every single value in this range.
The inequality signs are;
- Greater than >
- Less than <
- Greater than or equal to ≥
- Less than or equal to ≤
- Equal to =
Learn more about inequality:
brainly.com/question/25275758
#SPJ1
I think the anser is c that what i think
Answer:
ummmmm ok u wanted someone to answer
Step-by-step explanation:
also do u have any song ideas
Answer:
9.9
Step-by-step explanation:
\text{Volume of Hemisphere}\text{:}
Volume of Hemisphere:
\,\,257
257
\text{Volume of Sphere}\text{:}
Volume of Sphere:
\,\,514
514
Double volume of hemisphere to get volume of the entire sphere
\text{Volume of a Sphere:}
Volume of a Sphere:
V=\frac{4}{3}\pi r^3
V=
3
4
πr
3
514=
514=
\,\,\left(\frac{4}{3}\pi\right) r^3
(
3
4
π)r
3
514=
514=
\,\,(4.1887902)r^3
(4.1887902)r
3
Evaluate 4/3pi in calc
\frac{514}{4.1887902}=
4.1887902
514
=
\,\,\frac{(4.1887902)r^3}{4.1887902}
4.1887902
(4.1887902)r
3
Evaluate \frac{4}{3}\pi
3
4
π in calc
122.7084611=
122.7084611=
\,\,r^3
r
3
\sqrt[3]{122.7084611}=
3
122.7084611
=
\,\,\sqrt[3]{r^3}
3
r
3
Cube root both sides
4.9692575=
4.9692575=
\,\,r
r
\text{Then the diameter equals }9.938515
Then the diameter equals 9.938515
diameter is radius times 2
\text{Final Answer:}
Final Answer:
d\approx 9.9\text{ m}
d≈9.9 m
Round to nearest tenth
