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REY [17]
3 years ago
14

a stomp rocket takes 1.5 seconds to reach its maximum height what was the initial velocity and what was the maximum height ?

Physics
2 answers:
Zinaida [17]3 years ago
5 0
1) Vf = Vo - gt; Vf = 0 => Vo = gt = 9.8m/s^2 * 1.5s = 14.7 m/s

2) d = Vo*t - gt^2 /2 = 14.7m/s*1.5 - 9.8m/s^2 * (1.5s)^2 / 2 = 11.02 m

 
Roman55 [17]3 years ago
5 0
Below is the solution:

1) Let the acceleration is a m/s^2 and the velocity after 4 sec is v m/s 
<span>=>By v = u + at </span>
<span>=>v = 4a ------------(i) </span>
<span>For 1st phase:- </span>
<span>=>By s = ut + 1/2at^2 </span>
<span>=>s1 = 0 + 1/2 x a (4)^2 </span>
<span>=>s1 = 8a --------------(ii) </span>
<span>For 2nd phase:- </span>
<span>=>By s = vt </span>
<span>=>s2 = 4a x (9.1-4) </span>
<span>=>s2 = 20.4a -------------(iii) </span>
<span>=>By (ii) + (iii):- </span>
<span>=>s1+s2 = 8a + 20.4a </span>
<span>=>100 = 28.4a </span>
<span>=>a = 3.52 m/s^2 </span>
<span>2)(a) By v = u -gt </span>
<span>=>0 = u - 9.8 x 1.5 </span>
<span>=>u = 14.7 m/s </span>
<span>(b) By v^2 = u^2 - 2gh </span>
<span>=>0 = (14.7)^2 - 2 x 9.8 x h </span>
<span>=>h = 11.03 m
</span>
Thank you for posting your question here. 

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