Question

Two iron bolts of equal Mass one at a hundred see another at 55 Sierra place in the insulated cylinder assuming the heat capacity of the container is negligible what is the final temperature inside the container

Answer 1

Answer:

$T_2 = 77.5c$

Explanation:

From the question we are told that

Temp of first bolts$T_1=100$

Temp of 2nd bolt $T_2=55$

Generally the equation showing the relationship between  heat & temperature is given by

  $q=cm \triangle T$

Generally heat released  by the iron bolt  = heat gained by the iron bolt

Generally solving mathematically

     $-(0.45*m* (T_2-100 \textdegree c)) = 0.45*m*(T_2 -55\textdegree c)$

     $-(T_2-100 \textdegree c)) = (T_2 -55 \textdegree c)$

      $T_2 +T_2= 100 \textdegree c+55 \textdegree c$

      $T_2=\frac{155 \textdegree c}{2}$

      $T_2 = 77.5 \textdegree c$

Therefore $T_2 = 77.5 \textdegree c$ is the final temperature inside the container