Ask question

Ask question

All categories

3 years ago

8

light of wavelength 485 nm passes through a single slit of width 8.32 *10^-6m. what is the single between the first (m=1) and se

cond (m=2) interference minima?

1 answer:

Assoli18 [71]3 years ago

3 0

Answer:

3.35

Explanation:

Got it on Acellus

You might be interested in

Three light bulbs are connected to a battery in a series circuit.How will the bulbs behave if the circuit is closed

Drupady [299]

The answer is

<em>All the three light bulbs will glow</em>

hope this helps

6 0

3 years ago

Read 2 more answers

F an object has a mass of 200 kg and a weight of 1000 N, what is g?

jeka94

Answer:

g = 5 m/s square

Explanation:

Weight(W), Mass(m), Gravity(g)

W = mg

1,000N = 200g

g = 1000/200

g = 5 m/s square

7 0

2 years ago

Which statement describes the law of conservation of energy?

dmitriy555 [2]

Answer:

D

Explanation:

cuz it transforms from one to another can't be created not destroyed.PERIOD!

6 0

3 years ago

Read 2 more answers

I beg you plz help me asap!!!

Strike441 [17]

Answer:

a.

Explanation:

there would be a new planet is our solar system which could cause different gravitation pull on all the planets also there could be possible be new life form or other valuable metals that haven't been discovered on this planet. hope this helps somewhat

8 0

3 years ago

Read 2 more answers

You are working at a company that manufactures electri- cal wire. Gold is the most ductile of all metals: it can be stretched in

Alona [7]

Explanation:

We know that the relation between volume and density is as follows.

Volume = $\frac{\text{mass}}{\text{density}}$

So, V = $\frac{10^{-3}}{19.3 \times 10^{3} kg/m^{3}}$

= $5.181 \times 10^{-8} m^{3}$

Now, we will calculate the area as follows.

Area = $\frac{\text{volume}}{\text{length}}$

= $\frac{5.181 \times 10^{-8} m^{3}}{2.4 \times 10^{3}}$

= $2.15 \times 10^{-11} m^{2}$

Formula to calculate the resistance is as follows.

R = $\rho \frac{l}{A}$

= $\frac{2.44 \times 10^{-8} \times 2400}{}2.15 \times 10^{-11}}$

= $2.71 \times 10^{6} ohm$

Thus, we can conclude that the resistance of given wire is $2.71 \times 10^{6} ohm$ .

4 0

3 years ago