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Nesterboy [21]
2 years ago
7

You are loading a toy dart gun, which has two settings, the more powerful with the spring compressed twice as far as the lower s

etting. If it takes 5.0 J of work to compress the dart gun to the lower setting, how much work does it take for the higher setting?
A. 20 J
B. 10 J
C. 2.5 J
D. 40 J
Physics
1 answer:
Amiraneli [1.4K]2 years ago
4 0

Answer:

option A

Explanation:

given,

compression for lower setting = x

work done to compress in lower setting = 5 J

compression in higher setting, x' = 2 x

work done in higher setting = ?

Work done in compression of spring at lower setting

W = \dfrac{1}{2}kx^2

5 = \dfrac{1}{2}kx^2............(1)

Work done in compression of spring at higher setting

W' = \dfrac{1}{2}kx'^2

W'= \dfrac{1}{2}k(2x)^2

W'= 4\times \dfrac{1}{2}kx^2

W'= 4\times W

from equation (1)

W'= 4\times 5

    W' = 20 J

Work take for the higher setting is equal to 20 J

Hence, the correct answer is option A

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Answer:

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Putting this paragraph in equations:

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Answer:

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