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Murrr4er [49]
2 years ago
6

Explain why an experiment should test only one variable at a time

Physics
1 answer:
padilas [110]2 years ago
4 0
We use only one variable at a time to find the accurate result. We want to see how the result of experiment changes everytime with a single variable.
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The human ear canal is, on average, 2.5cm long and aids in hearing by acting like a resonant cavity that is closed on one end an
Troyanec [42]

Answer:

3400 Hz

Explanation:

We know that

1 cm = 0.01 m

L = Length of the human ear canal = 2.5 cm = 0.025 m

V = Speed of sound = 340 ms⁻¹

f = First resonant frequency

The human ear canal behaves as a closed pipe and for a closed pipe, nth resonant frequency is given as

f = \frac{(2n - 1)V}{4L}

for first resonant frequency, we have n = 1

Inserting the values

f = \frac{(2(1) - 1) 340}{4(0.025)}

f = \frac{340}{4(0.025)}

f = 3400 Hz

4 0
3 years ago
What can Lisa do to increase the strength of the electromagnet?
drek231 [11]

Answer:

move the wire loops closer

Explanation:

because the closer t they are the more concentrated the energy is in that specific area

4 0
3 years ago
BRAINLIEST+10PTS: does ozone absorb just harmful UV rays? Or just a random portion of UV?
emmasim [6.3K]

Answer:As sunlight passes through the atmosphere, all UVC and most UVB is absorbed by ozone, water vapour, oxygen and carbon dioxide. UVA is not filtered as significantly by the atmosphere. Is there a connection between ozone depletion and UV radiation? Ozone is a particularly effective absorber of UV radiation.

Explanation:

I had old notes

4 0
2 years ago
Read 2 more answers
An infinite line of charge with linear density λ1 = 6 μC/m is positioned along the axis of a thick insulating shell of inner rad
Anna11 [10]

Answer: λ2= 2.34 * 10^-6 C/m

Explanation: In order to calculate the value of the  linear charge density of the insulating shell we have to multiply ρ* Volume of the hollow cylinder, so

Volume of cylinder:2*π*b*L *(b-a)  where (b-a) is the thickness, then

λ2=Q/L = 634 *10^-6 C/m^3* 2*π*0.042 m*(0.042-0.26)== 2.34 μ C/m

5 0
3 years ago
a 75-kg refrigerator is located on the 70th floor of a skyscraper (300 meters above ground). what is the potential energy of the
mart [117]
Here, you can calculate it's potential energy with respect to ground.
We know, U = mgh
Here, m = 75 Kg
g = 9.8 m/s²       [ constant value for earth system ]
h = 300 m

Substitute their values into the expression:
U = 75 × 9.8  × 300
U = 220500 J

In short, Your Final Answer would be 220,500 J 

Hope this helps!
8 0
3 years ago
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