The simplest compound of hydrocarbon is methane
- The formula is CH_4
- It belongs to alkane group and has single bonds.
The electron structure attached
The reason a tennis ball and a solid steel ball will accelerate at the same rate in the absence of air resistance is because the net force to mass ratio is the same for both objects.
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What is air resistance?</h3>
Air resistance is described as the forces that are in opposition to the relative motion of an object as it passes through the air.
The units for the force of air resistance are in Newtons (N).
Air resistance can be gotten by taking air density times the drag coefficient times area all over two, and then multiply by velocity squared.
So we can conclude that in the absence of air resistance, the horizontal velocity of the body is unaffected by any other external force as the only force which acts on the ball is gravity.
Learn more about air resistance at; brainly.com/question/9143942
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Explanation:
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The first collision because a greater amount of momentum must be taken and used in order to push the cart back, giving it a greater mass and impulse
Answer:
I2 = 3.076 A
Explanation:
In order to calculate the current in the second loop, you take into account that the magnitude of the magnetic field at the center of the ring is given by the following formula:
(1)
I: current in the wire
R: radius of the wire
μo: magnetic permeability of vacuum = 4π*10^-7 T/A
In the case of the two wires with opposite currents and different radius, but in the same plane, you have that the magnitude of the magnetic field at the center of the rings is:
(2)
I1: current of the first ring = 8A
R1: radius of the first ring = 0.078m
I2: current of the second ring = ?
R2: radius of the first second = 0.03m
To find the values of the current of the second ring, which makes the magnitude of the magnetic field equal to zero, you solve the equation (2) for I2:

The current of the second ring is 3.076A and makes that the magntiude of the total magnetic field generated for both rings is equal to zero.