Sm = small piston
la = large piston
P=F/A
P=15000/(20^2)π
F of sm = PA
= (75/2π)•((8^2)π)
= (75•64)/2
= 4800/2
= 2400N
We already know the pressure but giving it in an approximate decimal form, to two significant figures (since that's what your supplied precision is at):
a) 12 Pa
b) 2400 N
Answer:
KE = 1/2 M v^2 kinetic energy of projectile
KE = 1/2 * 20 * (54 m/s)^2 = work done on projectile
W = 10 * 54^2 = work done on projectile
W = 29,160 J
Answer:
Explanation:
Constant pressure molar heat capacity Cp = 29.125 J /K.mol
If Cv be constant volume molar heat capacity
Cp - Cv = R
Cv = Cp - R
= 29.125 - 8.314 J
= 20.811 J
change in internal energy = n x Cv x Δ T
n is number of moles , Cv is molar heat capacity at constant volume , Δ T is change in temperature
Putting the values
= 20 x 20.811 x 15
= 6243.3 J.
Answer: no
Explanation: we need a picture
Answer:
D. The speed of the combined vehicles is less than the initial speed of the truck.
Explanation:
Ik this is late
