Question

2, 6, 18, 54. 162,...

Answer 1

9514 1404 393

Answer:

  $\text{c. }f(n)=3f(n-1);f(1)=2$

Step-by-step explanation:

The first term is 2, so part of the recursive definition is ...

  f(1) = 2

The common ratio is 6/2 = 3, so each term is 3 times the previous one. That part of the recursive definition is ...

  f(n) = 3·f(n -1)

These two parts of the definition match choice C.