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Klio2033 [76]
3 years ago
9

Is A’B’C’ congruent to ABC explain why or why not

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0

Answer:

Is there a picture?

Step-by-step explanation:

please add a picture. You can also see if the transition is congruent by counting

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Answer to 5 and 6 please?​
yKpoI14uk [10]

Answer:

5. ST  6. AT

Step-by-step explanation:

For a product to be divisible by a number, one of the factors must be that number. This can be achieved by one of the consecutive numbers being that number, or a multiple of that number.

5. 4 x 5 x 6 = 120 which is divisible by 5

1 x 2 x 3 = 6 which is not divisible by 5

6. 1 x 2 x 3 = 6 which is divisible by 6

2 x 3 x 4 = 24 which is divisible by 6

3 x 4 x 5 = 60 which is divisible by 6

4 x 5 x 6 = 120 which is divisible by 6

And now we will just repeat ourselves.

7 0
3 years ago
Find the sum of 12a + 7b, −6a − 9, and 14a − 12b.
Ivan
The answer is:  [A]:  " 20a − 5b − 9 " .
______________________________________
Explanation:
_______________________________________________
  (12a <span>+ 7b) + (−6a − 9) + (14a − 12b) =
 
   12a </span><span>+ 7b  +  1(−6a − 9) + 1(14a − 12b) =
</span>    
   12a + 7b + (1*-6a) + (1*-9) + (1*14a) + (1* -12b) =
      
    12a + 7b − 6a − 9 + 14a − 12b =  ?

Combine the "like terms:

12a − 6a  + 14a = 20a ; 

7b − 12b =  - 5b ;

and then we have "-9" ;
_____________________________________________________
So, write as:   " 20a − 5b − 9 " ;  which is:  Answer choice:  [A].
______________________________________________________
8 0
3 years ago
Read 2 more answers
4x+6y = 36 in slope intercept form ?
svlad2 [7]

Answer:

y = -2/3x + 6

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
y=c1e^x+c2e^−x is a two-parameter family of solutions of the second order differential equation y′′−y=0. Find a solution of the
vagabundo [1.1K]

The general form of a solution of the differential equation is already provided for us:

y(x) = c_1 \textrm{e}^x + c_2\textrm{e}^{-x},

where c_1, c_2 \in \mathbb{R}. We now want to find a solution y such that y(-1)=3 and y'(-1)=-3. Therefore, all we need to do is find the constants c_1 and c_2 that satisfy the initial conditions. For the first condition, we have:y(-1)=3 \iff c_1 \textrm{e}^{-1} + c_2 \textrm{e}^{-(-1)} = 3 \iff c_1\textrm{e}^{-1} + c_2\textrm{e} = 3.

For the second condition, we need to find the derivative y' first. In this case, we have:

y'(x) = \left(c_1\textrm{e}^x + c_2\textrm{e}^{-x}\right)' = c_1\textrm{e}^x - c_2\textrm{e}^{-x}.

Therefore:

y'(-1) = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e}^{-(-1)} = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e} = -3.

This means that we must solve the following system of equations:

\begin{cases}c_1\textrm{e}^{-1} + c_2\textrm{e} = 3 \\ c_1\textrm{e}^{-1} - c_2\textrm{e} = -3\end{cases}.

If we add the equations above, we get:

\left(c_1\textrm{e}^{-1} + c_2\textrm{e}\right) + \left(c_1\textrm{e}^{-1} - c_2\textrm{e}  \right) = 3-3 \iff 2c_1\textrm{e}^{-1} = 0 \iff c_1 = 0.

If we now substitute c_1 = 0 into either of the equations in the system, we get:

c_2 \textrm{e} = 3 \iff c_2 = \dfrac{3}{\textrm{e}} = 3\textrm{e}^{-1.}

This means that the solution obeying the initial conditions is:

\boxed{y(x) = 3\textrm{e}^{-1} \times \textrm{e}^{-x} = 3\textrm{e}^{-x-1}}.

Indeed, we can see that:

y(-1) = 3\textrm{e}^{-(-1) -1} = 3\textrm{e}^{1-1} = 3\textrm{e}^0 = 3

y'(x) =-3\textrm{e}^{-x-1} \implies y'(-1) = -3\textrm{e}^{-(-1)-1} = -3\textrm{e}^{1-1} = -3\textrm{e}^0 = -3,

which do correspond to the desired initial conditions.

3 0
3 years ago
?????????????????????????
nasty-shy [4]
6 pounds.



First, find the amount she spent. 70 - 18.88 = 51.12

Now, just divide 51.12 by the cost per pound. 51.12 / 8.52 = 6

So, Karen purchased 6 pounds of coffee.



Please consider marking this answer as Brainliest to help me advance.
6 0
3 years ago
Read 2 more answers
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