PLEASE HELP ME ASAP, PLEASE I NEED HELP

What is the variance of the following data? If necessary, round your answer to two decimal places. 17, 13, 13, 22, 11, 20

Bond [772]

Variance is the standard deviation squared but we're not going to use that now. Let's first calculate the mean:

mean = (17+13+13+22+11+20)/6 = 16.

Now for each value, let's see how far it is from this mean. We'll square these distances and average them. That's our variance.

17 distance 1 squared = 1
13 distance 3 squared = 9
13 distance 3 squared = 9
22 distance 6 squared = 36
11 distance 5 squared = 25
20 distance 4 squared = 16

Now average these outcomes:

variance = (1+9+9+36+25+16)/6 = 16.

So the variance by coincidence is the same as the mean.

Answer C is your answer.

7 0

4 years ago

What is 178÷2???????

Nonamiya [84]

178÷2 is 89
Hope this was helpful!

8 0

4 years ago

Read 2 more answers

A student theatre charges $9.50 per ticket. The theater has already sold 70 tickets. Write and solve an inequality that represen

Leona [35]

To make the inequality, we will use the ≥ sign to determine how many more tickets we will need. Before we write the inequality, let's see how much money was already made by the present tickets. 70 x 9.50 = $665.
We can write the inequality as $665 + $9.50t ≥ $1000 where t is the number of tickets sold. Now we can solve
$665 + $9.50t ≥ $1000, subtract 665
$9.50t ≥ $335. Now isolate the t by divide 9.50 to both sides
t ≥ 35.26 which we can round up to 36 because you cant sell 35.26 tickets.
So you need at least 36 more tickets to earn at least $1000

5 0

3 years ago

The function f(x) = −x^2 − 5x + 50 shows the relationship between the vertical distance of a diver from a pool's surface f(x), i

pychu [463]

Set the function to equal zero:

$-x^2 - 5x + 50 = 0$

To find the zeros, or solutions, to this problem, we will use the quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plug the values into the equation:

$a = -1, b = -5, c = 50$

$x=\frac{5\pm\sqrt{-5^2-4(-1)(50)}}{2(-1)}$

$x=\frac{5\pm\sqrt{25+200}}{-2}$

$x=\frac{5\pm15}{-2}$

Solve for both plus and minus:

$\frac{5 + 15}{-2} = \frac{20}{-2} = -10$

$\frac{5 - 15}{-2} = \frac{-10}{-2} = 5$

$x = -10, x = 5$

The question cannot use a negative value for x, as the diver cannot dive a negative distance from the board.

The answer is '<span>x = 5; the diver hits the water 5 feet away horizontally from the board', because x represents the horizontal distance away from the board.</span>

4 0

3 years ago

A coin will be tossed three times, and each toss will be recorded as heads (H) or tails (T). Give the sample space describing al

cricket20 [7]

Answer:

Sample space:

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

Third toss is heads:

{HHT, HTT, THT, TTT}

First toss is heads, second tails and third heads:

{HTH}

Explanation:

In order to find the sample space we need to write all the possible outcomes from tossing the coin three times.You can start by writting all the possible outcomes for the first toss being a head and finish with all the possible outcomes for the first toss being Tails. The number of elements in the sample space can be found by multiplying the possible outcomes of each toss together, so 2*2*2=8

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

For the third toss being heads we will have one restriction this time. Which is that the third toss is Tails. You can take the elements from the sample space where the third element is a tails. In this case, the number of elements can be calculated by multiplying the possible outcomes for only the first two tosses 2*2=4

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

For first toss is heads, second tails and third heads there is only one possible way for you to get this outcome so there is only one element to this set.

{HTH}

4 0

3 years ago