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boyakko [2]
2 years ago
6

-100 = -t/5 - 4Find t please! (also explain)​

Mathematics
2 answers:
Damm [24]2 years ago
6 0

Answer:

t = 480

Step-by-step explanation:

When we have equations with variables, we always want to isolate the variable, so lets get rid of 4 first.

Add 4 to both sides :

-96 = -t/5

Multiply both sides by the denominator :

-480 = -t

Divide both sides by negative 1 :

t = 480

rodikova [14]2 years ago
3 0

Answer:

Step-by-step explanation:

-t/5 - 4 = -100

-t/5 = -96

t/5 = 96

t = 480

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Will ran the diagonal distance across a square field measuring 40 yards on each side. James ran the diagonal distance across a r
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Answer: The distance across a rectangular field is longer distance.

Step-by-step explanation:

Since we have given that

Dimension of square = 40 yards

So, Dimensions of rectangle are :

Length = 25 yards

Width = 35 yards

So, Perimeter of rectangle would be

2\times (l+b)\\\\=2\times (25+35)\\\\=2\times 60\\\\=120\ yards

Diagonal of square would be

\sqrt{40^2+40^2}\\\\=\sqrt{1600+1600}\\\\=\sqrt{3200}\\\\=56.56\ yards

Hence, the distance across a rectangular field is longer distance.

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3 years ago
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Factor the following expression. 36y - 12
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Hey there!


36y - 12


FIRST LOOK AT THE GCF (Greatest Common Factor)


36y: 1, 2, 3, 4, 6, 9, 12, 18, 36, and y


12: 1, 2, 3, 4, 6, and 12


GCF: 12


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12(?y - 1)


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Answer: 12(3y - 1)


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2 years ago
What is 0.6144 divided by 1.6
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Write an equation in slope-intercept form for the line that passes through the point  ( -1 , -2 )  and is perpendicular to the l
mamaluj [8]

The equation in slope-intercept form for the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5 is y = \frac{3}{4}x - \frac{5}{4}

<em><u>Solution:</u></em>

<em><u>The slope intercept form is given as:</u></em>

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given that the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5

Given line is perpendicular to  − 4 x − 3 y  =  − 5

− 4 x − 3 y  =  − 5

-3y = 4x - 5

3y = -4x + 5

y = \frac{-4x}{3} + \frac{5}{3}

On comparing the above equation with eqn 1, we get,

m = \frac{-4}{3}

We know that product of slope of a line and slope of line perpendicular to it is -1

\frac{-4}{3} \times \text{ slope of line perpendicular to it}= -1\\\\\text{ slope of line perpendicular to it} = \frac{3}{4}

Given point is (-1, -2)

Now we have to find the equation of line passing through (-1, -2) with slope m = \frac{3}{4}

Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1

-2 = \frac{3}{4}(-1) + c\\\\-2 = \frac{-3}{4} + c\\\\c = - 2 + \frac{3}{4}\\\\c = \frac{-5}{4}

\text{ substitute } c = \frac{-5}{4} \text{ and } m = \frac{3}{4} \text{ in eqn 1}

y = \frac{3}{4} \times x + \frac{-5}{4}\\\\y = \frac{3}{4}x - \frac{5}{4}

Thus the required equation of line is found

8 0
2 years ago
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