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ra1l [238]
2 years ago
15

Which of the following best decribes ​

Physics
1 answer:
GalinKa [24]2 years ago
5 0
A b or c I love d n me l101
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Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. one force is 9.0 n, acting due east, an
Zolol [24]
The first thing you should do for this case is to find the horizontal and vertical components of the forces acting on the body.
 We have then:
 Horizontal = 9-9.2cos (58) = 4.124742769 N.
 Vertical = 9.2sin (58) = 7.802042485 N
 Then, the resulting net force is:
 F = √ ((4.124742769) ^ 2 + (7.802042485) ^ 2) = 8.825268826 N
 Then by definition:
 F = m * a
 Clearing the acceleration:
 a = F / m
 a = (8.825268826) / (3.0) = 2.941756275 m / s ^ 2
 answer:
 The magnitude of the body's acceleration is
 2.941756275 m / s ^ 2
6 0
3 years ago
explain how the temperature of the earth is maintained and how it’s affected by other factors (6 marks)
nikklg [1K]

Answer:

The temperature of the Earth depends on many factors, including the concentration of greenhouse gases such as water vapour, methane and carbon dioxide. The Earth's temperature also depends on the rates at which light radiation and infrared radiation are: absorbed by the Earth's surface and atmosphere.

6 0
2 years ago
Suppose you average 75 MPH over the first halfof a drive, and your average speed for the entiredrive is 60 MPH. What was your av
alexandr402 [8]

Answer:

x = 45 MPH

Explanation:

given,

Average speed of the first half = 75 MPH

Average speed of entire ride = 60 MPH

Average speed of the second half = ?

let the average speed of the second half = x MPH

now,

average of entire ride is given as 60 mph so,

 \dfrac{75+x}{2} = 60

 75+x= 2\times 60

       75 + x = 120

         x = 120 -75

        x = 45 MPH

hence, the average speed of the second half comes out to be 45 MPH.

5 0
3 years ago
Using an analogy of a water balloon, describe the function of the bladder. (2 points)
a_sh-v [17]

Answer:

it fucntions

Explanation:

7 0
3 years ago
Read 2 more answers
A 61.5 KG student sits at a desk 1.2 5M away from a 70.0 KG student. What is the magnitude of the gravitational force between th
muminat

mass of two students are

m_1 = 61.5 kg

m_2 = 70 kg

distance between them is given as

r = 1.25 m

now gravitational force between them is given as

F = \frac{Gm_1m_2}{r^2}

now plug in all values

F = \frac{6.67\times 10^{-11} \times 61.5 \times 70}{1.25^2}

F = 1.84 \times 10^{-7} N

so above is the force of gravitation between them

6 0
3 years ago
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