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Rainbow [258]
3 years ago
13

The type of function that describes the amplitude of damped oscillatory motion is _______. The type of function that describes t

he amplitude of damped oscillatory motion is _______. quadratic sinusoidal inverse exponential linear
Physics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

exponential

Explanation:

type of function that describes the amplitude of damped oscillatory motion is exponential because as we know that here function is

y = A × e^{\frac{-bt}{2m}}  × cos(ωt + ∅ )    ..................................... ( 1 )          

here function A × e^{\frac{-bt}{2m}}   is amplitude

as per equation ( 1 )it is exponential

so that we can say that amplitude of damped oscillatory motion is exponential

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Suppose the original segment of wire is stretched to 10 times its original length. How much charge must be added to the wire to
Debora [2.8K]

Here we want to study how the linear charge density changes as we change the measures of our body.

We will find that we need to add 9*Q of charge to keep the linear charge density unchanged.

<em>I will take two assumptions:</em>

The charge is homogeneous, so the density is constant all along the wire.

As we work with a linear charge density we work in one dimension, so the wire "has no radius"

Originally, the wire has a charge Q and a length L.

The linear charge density will be given by:

λ = Q/L

Now the length of the wire is stretched to 10 times the original length, so we have:

L' = 10*L

We want to find the value of Q' such that λ' (the <u>linear density of the stretched wire</u>) is still equal to λ.

Then we will have:

λ' = Q'/L' = Q'/(10*L) = λ = Q/L

Q'/(10*L) = Q/L

Q'/10 = Q

Q' = 10*Q

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If you want to learn more, you can read:

brainly.com/question/14514975

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3 years ago
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A space vehicle is traveling at 2980 km/h relative to Earth when the exhausted rocket motor is disengaged and sent backward. The
Strike441 [17]

Answer:

3054.4 km/h

Explanation:

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let v be the new speed of the motor so that the

new momentum = 4Mv and the new momentum of the module  = M ( v + 94 km/h )

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8 0
3 years ago
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