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arsen [322]
3 years ago
13

What is this process called when a liquid turns into gas

Physics
1 answer:
aev [14]3 years ago
3 0

Answer:

evaporation

Explanation:

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A 20.0 μF capacitor initially charged to 30.0 μC is discharged through a 1.20 kΩ resistor. How long does it take to reduce the c
Kay [80]

Answer:

16.6 ms or 0.0166 s

Explanation:

If Q is the final charge, Q' is the initial charge, C the capacitance ,R is the resistance , t the time taken  and τ the time constant,

[tex]Q = Q'( 1- e^{-t\div \tau })

τ = R C = (1.20×10³) (20×10⁻⁶) = 0.024 s

15 = 30 ( 1- e^{-t\div \ 0.024 })

( 1- e^{-t\div \ 0.024 }) = 15 ÷ 30

⇒ - e^{-t\div \ 0.024 }) = 0.5 -1  

⇒  e^{-t\div \ 0.024 }) = 0.5

Taking logarithm to the base e on both sides of this equation,

⇒ t = 0.0166 seconds = 16.6 milli seconds

3 0
3 years ago
Velocity vs Time
Grace [21]

Answer:

A and C

C

40 m/s

zero

Explanation:

8 0
3 years ago
A 100 Ω resistor is connected in series with a 47 µF capacitor and a source whose maximum voltage is 5 V, operating at 100.0 Hz.
Pani-rosa [81]

Answer:

X_c=-33.86275385\Omega

|Z|=105.5778675\Omega

I=0.04735841062A

\phi=20.78612878\°

Explanation:

The electrical reactance is defined as:

X_c=-\frac{1}{2\pi fC}

Where:

f=Frequency\\C=Capacitance

So, replacing the data provided by the problem:

X_c=\frac{1}{2\pi *100*(47*10^{-6} )} =-33.86275385\Omega

Now, the impedance can be calculated as:

Z=R+jX_c

Where:

R=Resistance\\X_c= Capacitive\hspace{3}reactance

Replacing the data:

Z=100-j33.86275385

In order to find the magnitude of the impedance we can use the next equation:

|Z|=\sqrt{(R^2)+(X_c^2)}=\sqrt{(100)^2+(-33.86275385)^2} =105.5778675\Omega

We can use Ohm's law to find the current:

V=I*Z\\I=\frac{V}{Z}

Therefore the current is:

I=\frac{5}{100-j33.86275385}=0.04485638113+0.01518960593j

And its magnitude is:

|I|=\sqrt{(0.04485638113)^2+(0.01518960593)^2} =0.04735841062\Omega

Finally the phase angle of the current is given by:

\phi=arctan(\frac{0.01518960593}{0.04485638113})=20.78612878\°

5 0
3 years ago
Leftover planetesimals that formed in the region of the solar system now occupied by the jovian planets are called
rewona [7]

Answer:

Comets

Explanation:

Comets are planetary celestial bodies consisting of ice and dust, sometimes rocky particles  formed in the region of the solar system. Long-period comets propagate towards the Sun by gravitational perturbations caused by passing stars. Some comets usually hyberbolic comets, move through the inner Solar System  prior to entering the interstellar region. Short period comet lies beyond the orbit of the Neptune.

The Jovian planets include Jupiter, Saturn, Uranus, and Neptune.

Therefore, leftovers of comets (planetesimal bodies) formed in the region of the solar system that are now occupied by the Jovian planets is due to the dusty particles  associated with the comets.

7 0
3 years ago
An object has a kinetic energy of 275 j and a momentum of magnitude 25.0 kg · m/s. find the (a) speed and (b) mass of the object
Sergeu [11.5K]
Kinetic energy = momentum^2 / 2 x mass
Mass = (momentum^2/ Kinetic energy) / 2

Mass =  (25^2 / 275) / 2
Mass = 1.136 kg.

momentum = mass x velocity

velocity = mass / momentum
velocity = 1.136 / 25
velocity = 0.04544 m/s
8 0
3 years ago
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