Answer:
(x + 14)² + (y – 21/2)² = 1
Step-by-step explanation:
The equation of a circle can be written as seen below
(x – h)² + (y – k)² = r²
Where (h,k) is at the center and r = radius
We are given that the radius is 1
We are also given that the center is at (-14,21/2)
So we know that r = 1, h = -14, and k = 21/2
So to find the equation of the circle we simply substitute these values into the equation of a circle
Equation of a circle: (x – h)² + (y – k)² = r²
r = 1, h = -14, and k = 21/2
Substitute values
(x – (-14))² + (y – 21/2)² = 1²
1^2 = 1
The two negative signs before the 14 cancel out and it changes to + 14
The equation of a circle with a center at (-14,21/2) and a radius of 1 is (x + 14)² + (y – 21/2)² = 1
Answer: i dont really know if im right but here! :L
Step-by-step explanation: Now, say G is an Abelian group, finitely generated from generator In this sense abelian groups are “more interesting” than vector spaces. and in the table below, the second last column is the identity, while the last column is cyclic of order 4, with 9g the generator
No you had it right, it is around the 18 / 3 and the 5 + 1
The answer is y=207 hope this helps
