Answer:
≈ 345.8 ft
Step-by-step explanation:
There is a right triangle formed by Bonnie's height (h) the ground and the angle of elevation.
Using the tangent ratio in the right triangle
tan20° = 
= 
( multiply both sides by 950 )
950 × tan20° = h , thus
h ≈ 345.8 ft ( to 1 dec. place )
Answer:
The area of an equilateral triangle with the side of 6 inches = 15.59 inches²
Step-by-step explanation:
Formula:-
Area of equilateral triangle = √3a²/4
Where 'a' is the side of equilateral triangle.
<u>To find the area of given triangle</u>
Here side a = 6 inches
Area = √3a²/4
= (√3 * 6²)/4
= (1.73 * 36)/4 = 1.73 * 9 = 15.59 inches²
Answer:
38 degrees
Step-by-step explanation:
this is an isosceles triangle, meaning that the base angles are congruent.
the total triangle is equal to 180
so the equation would be: x=180 - (71+71)
evaluate:
x=180-142
x=38 degrees
Hope this helps :)
Answer:
0.2
Step-by-step explanation:
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way
Step-by-step explanation:
- From a standard deck of cards, one card is drawn. What is the probability that the card is black and a
jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
- A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen
or an ace.
P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13
- WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces?
P(AA) = (4/52)(3/51) = 1/221.
- WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king?
P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed.
- WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the
probability of drawing the first queen which is 4/52.
- The probability of drawing the second queen is also 4/52 and the third is 4/52.
- We multiply these three individual probabilities together to get P(QQQ) =
- P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
- Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
