Answer:
The answer to your question is: 2.75 x 10 ²¹ atoms
Explanation:
Data
H₃PO₄
mass = 0.1488 g
MW H₃PO₄ = 3 + 31 + (16 x 4) = 98g
98 g of H₃PO₄ ------------------ 3 g of H₂
0.1488 g H₃PO₄ --------------- x
x = 0.0046 g of H₂
1 g of H₂ ------------------- 6.023 x 10²³ atoms
0.0046 g of H₂ -------------- x
x = (0.0046 x 6.023 x 10²³) / 1
x = 2.75 x 10 ²¹ atoms
Answer:
4 mol of KOH would produce 116.6 g of Mg(OH)₂
Explanation:
According to the following balanced equation:
- MgCl₂+ 2 KOH -----> Mg(OH)₂ + 2 KCL
One can note that 2 mol of KOH react with MgCl₂ to produce 1 mol of Mg(OH)₂.
using cross multiplication
2 mol of KOH → 1 mol of Mg(OH)₂.
4 mol of KOH → ?? mol of Mg(OH)₂.
no of moles of Mg(OH)₂ = (1 mol* 4 mol) / 2 mol =2 mol
Now we can convert moles of Mg(OH)₂ to grams using the formula
mass of Mg(OH)₂= (no. of moles * molar mass) = (2 mol * 58.3g/mol) = 116.6 g
- So, 4 mol of KOH would produce 116.6 g of Mg(OH)₂.
<u>Given:</u>
Mass of asteroid, M1 = 5.00*10¹² kg
Velocity of asteroid V1 = 15.0 km/s
Mass of moon, M2 = 7.36*10²² kg
<u>To determine:</u>
The recoil velocity of moon, V2
<u>Explanation:</u>
Since the collision is perfectly inelastic, momentum is conserved. therefore,
M1 * V1 = M2* V2
V2 = M1*V1/M2 = 5.00*10¹² *15.0 /7.36*10²² = 1.02*10⁻⁹ km/s
