The answer : 4 sin c sin b sin a

Step by step
Formula = A+b+c = 180

B+c = 180-A

C+A= 180-B

A+B= 180-c

2 sin c • 2 cos a-b+c/ 2 cos a-b-c / 2

4 sin c cos 180-2b/2 cos a-(180-a)/ 2

4 sin c cos (90-b ) cos ( A-90)

4 sin c sin b sin A

5 0

4 years ago

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Can u help me pls they are exponents with multiplication and division

Ronch [10]

When there is a multiplication involving exponents, we need to evaluate the numbers and each variables separately. In this case, we have 5 and 4 as the numbers, and w and h for the variables.

When we multiply 5 and 4 we get:
$5 \times 4 = 20$

For w, we have ${w}^{6}$ , ${w}^{4}$ , $w$ . While we are multiplying the w's, we need to add the exponents together to get the final answer: ${w}^{6} \times {w}^{4} \times w = {w}^{11}$

For h's, there are ${h}^{2}$ , ${h}^{5}$ , ${h}^{4}$ . When we apply the same thing to h's, we get ${h}^{2} \times {h}^{5} \times {h}^{4} = {h}^{11}$

For the final step, we need to write all of these together: $20 \times {w}^{11} \times {h}^{11} \: \: or \: \: 20 {w}^{11} {h}^{11} \: \: or \: \: 20 {(wh)}^{11}$

3 0

4 years ago