Answer:
Dissolving ice tea mix in water is a chemical change
Explanation:
It is a chemical change because you can not bring back the ice tea mix back if you mix it in water.
Hope it helps
Ideal Gas equation will be used assuming all the gases are acting Ideally,
P V = n R T
Solving for V,
V = n R T / P ----- (1)
Standard Temperature = 273 K
Standart Pressure = 1 atm
Gas Constant R = 0.08206 atm.L.mol⁻¹.K⁻¹
1) For 1.7 mole of H₂;
Putting values in eq.1,
V = (1.7 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 273 K) ÷ 1 atm
V = 38.08 L
2) For 1.8 ×10⁻² mole of N₂;
Putting values in eq.1,
V = (1.8 ×10⁻² mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 273 K) ÷ 1 atm
V = 0.403 L
3) For 2.5 ×10² mole of O₂;
Putting values in eq.1,
V = (2.5 ×10² mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 273 K) ÷ 1 atm
V = 5600 L
Answer:
0.544 eV; Ag is a smaller atom.
Explanation:
1. Ionization energy of hydrogen
The outermost electrons in Rb and Ag are in 5s orbitals.
The formula for the energy of an electron in a hydrogen atom is
E = -13.6/n² eV
For a hydrogen atom in a 5s orbital,
E = -13.6/5² = -13.6/25 = -0.544 eV
The ionization energy would be 0.544 eV.
2. Rb vs Ag
The first electrons to be removed from Rb and Ag are in 5s orbitals.
The atomic radius of Ag is less than that of Rb because, as you go from left to right across the Row, you are adding 10 protons to the nucleus and 10 electrons to the outer shell.
The added electrons do not effectively shield each other from the attraction of the nucleus, so the 5s electron of Ag is closer in.
It takes more energy to remove the electron from silver, so the ionization energy of Ag is greater than that of Rb.
An isotope is an element with a different number of neutrons than protons. Neutrons have mass and therfore elements can have different masses while being the same element.
Answer: Tens place.
Step-by-step explanation: hmm wait one moment
